Answer:
The one on the top left should be your answer
Let me know if you got it right!
Answer:
17.5%
Step-by-step explanation:
First of all, see this situation as a cumulative binomial distribution. You have isolated trials with a probability of success. This makes it binomial. The wording of the question "what is the probability of at least half..." makes this cumulative.
There are a few ways to calculate this, and I'm not quite sure which way you're familiar with. I'll show the cumbersome way and use wolfram to make the calculation.
First, I'll calculate the probability for 15 success, given 30 trials.
30c15*0.4^15*0.6^15
Since the question asks for the probability of at least 15 success, I'll have to make a calculation for the probability of 16 successes, then 17, and so on. Then I'll have to add all the probabilities together. So, I'll use wolfram for that (see attached)
Answer:
Roughly 16 million bacteria.
Step-by-step explanation:
Multiply the rate of the bacteria going through mitosis times the amount of daughter cells per hour, for this case.
<em>r x (m)ms x hr</em> <em>= </em>bacteria in one day
Hope this helps!
<em>note: ms and hr are millisecond and hour</em>
The answer is 38 over 100 cups. Simplified = 19 over 50. All you do to get the answer is put 38 over 100. Then divide 38 by 2. Then divide 100 by 2.