Answer:
Option (A) 0.40951
Step-by-step explanation:
We are given the following information in the question:
P(target) = 0.90
Let the random variable X represent the number of times he hits ring of the target with a shot of the arrow.
The probability distribution of X is
x: 0 1 2 3 4 5
P(x): 0.00001 0.00045 0.00810 0.07290 0.32805 0.59049
The mean of discrete probability distribution is given by:
Now, we have to evaluate
Option (A) 0.40951 t is the probability that the number of times Luke will hit the inner ring of the target out of the 5 attempts is less than the mean of X.
Answer: Coin B And Coin C
Step-by-step explanation:
In 1, t<span>here are 6 outcomes for each die, so for three dice, the total combination is 6 x 6 x 6 = 216 outcomes. Hence, t</span><span>he probability of any individual outcome is 1/216 </span>
The outcomes that will add up to 6 are
<span>1+1+4 </span>
<span>1+4+1 </span>
<span>4+1+1 </span>
<span>1+2+3 </span>
<span>1+3+2 </span>
<span>2+1+3 </span>
<span>2+3+1 </span>
<span>3+1+2 </span>
<span>3+2+1 </span>
<span>2+2+2 </span>
<span>Hence the probability is </span><span>10/216 </span>
In 3, the minimum sum of the three dice is 3. so we start with this
<span>P(n = 3) </span>
<span>1+1+1 ; </span><span>1/216 </span>
<span>P(n = 4) </span>
<span>1+1+2 </span>
<span>1+2+1 </span>
<span>2+1+1 ; </span><span>3/216 </span>
<span>P(n = 5) </span>
<span>1+1+3 </span>
<span>1+3+1 </span>
<span>3+1+1 </span>
<span>1+2+2 </span>
<span>2+1+2 </span>
<span>2+2+1; </span><span>6/216
The sum in 3 is 10/216 or 5/108</span>
Answer:
Step-by-step explanation:
let the integers be x and y
x+y=-20
y=-20-x
xy=99
x(-20-x)=99
-20x-x²=99
x²+20x+99=0
x²+11x+9x+99=0
x(x+11)+9(x+11)=0
(x+11)(x+9)=0
x=-11,-9
when x=-11
-11+y=-20
y=-20=11=-9
when x=-9
-9+y=-20
y=-20+9=-11
so integers are -11,-9
Answer
Step-by-step explanation:
A=2πrh+2πr2=2·π·3·6+2·π·32≈169.646
