All categories

2 years ago

29, 58,116, Find the 7th term.

Mathematics

1 answer:

prohojiy [21]2 years ago

5 0

9514 1404 393

Answer:

1856

Step-by-step explanation:

The numbers given do not have a common difference, but they do have a common ratio:

58/29 = 116/58 = 2

The general term of a geometric sequence with first term a1 and common ratio r is ...

an = a1×r^(n-1)

For this sequence, a1=29 and r=2, so the general term is ...

an = 29×2^(n-1)

Then the 7th term is ...

a7 = 29×2^(7-1) = 29×64 = 1856

The 7th term is 1856.

_____

If you prefer, you can double each term until you have 7 of them.

29, 58, 116, 232, 464, 928, 1856, ...

You might be interested in

Determine if the specified linear transformation is (a) one-to-one and (b) onto. Justify your answer. T: , T()(,),

xz_007 [3.2K]

Answer:

C. T is not one-to-one because the standard matrix A has a free variable.

Step-by-step explanation:

Given

$T(x_1,x_2,x_3) = (x_1-5x_2+4x_3,x_2 - 6x_3)$

Required

Determine if it is linear or onto

Represent the above as a matrix.

$T(x_1,x_2,x_3) = \left[\begin{array}{ccc}1&-5&4\\0&1&-6\\0&0&0\end{array}\right] \left[\begin{array}{c}x_1&x_2&x_3\end{array}\right]$

From the above matrix, we observe that the matrix does not have a pivot in every column.

This means that the column are not linearly independent, & it has a free variable and as such T is not one-on-one

8 0

3 years ago

18 less than 14 times a is 80

miss Akunina [59]

14a-18=80

14a=98

98/14 =a

a=7

3 0

3 years ago

|4a|=20<br> PLEASE HELPPPPPPPPPP

fgiga [73]

Answer:

The answer to |4a|=20 is a=5 or a=-5.

Step-by-step explanation:

6 0

3 years ago

I need someone to solve this problem for me please

Amiraneli [1.4K]

First, solve the area of the entire large rectangle (28)(45) = 1260
Next, find the area of the chunk that is cut out (11)(15) = 165
- we know the width is 15 because 45 - 6 - 24
Subtract the cut out piece from the overall rectangle 1260 - 165 = 1095

7 0

3 years ago

Read 2 more answers

Unit 4 Test, Part 2: Congruence and Constructions<br> Help with my math please

lakkis [162]

Answer/Step-by-sep explanation:

1. Given:

∆NMK ≅ ∆TRP

$\overline{NM} = 20$

$\overline{MK} = 15$

$\overline{KN} = 25$

$\overline{TR} = 3x - 1$

a. To complete the congruent statement, thus: ∆MNK ≅ ∆RTP

b. The side that is congruent to $\overline{TR}$ is $\overline{NM}$ . Thus:

$\overline{TR}$ ≅ $\overline{NM}$

c. Since $\overline{TR}$ ≅ $\overline{NM}$ , therefore:

$\overline{TR} = \overline{NM}$

$3x - 1 = 20$ (substitution)

Add 1 to both sides

$3x = 20 + 1$

$3x = 21$

Divide both sides by 3

$x = \frac{21}{3}$

$x = 7$

2. a. Slope of LK = $\frac{rise}{run} = \frac{4}{3}$

Slope of LM = $\frac{rise}{run} = -\frac{3}{5}$

b. ✍️Length of LK is the distance between L(-7, 4) and (-4, 8):

$Lk = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$Lk = \sqrt{(-4 -(-7))^2 + (8 - 4)^2}$

$Lk = \sqrt{(3)^2 + (4)^2}$

$Lk = \sqrt{9 + 16}$

$Lk = \sqrt{25}$

$Lk = 5$

✍️Length of LM is the distance between L(-7, 4) and (-2, 1):

$LM = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$LM = \sqrt{(-2 -(-7))^2 + (1 - 4)^2}$

$LM = \sqrt{(5)^2 + (-3)^2}$

$LM = \sqrt{25 + 9}$

$LM = \sqrt{34}$

$LM = 5.8$ (nearest tenth)

∆KLM is not an isosceles ∆ because it does not has two equal side lengths. This we can see because LK and LM are not equal.

Therefore, Anthony is incorrect. Am isosceles ∆ has two equal sides.

8 0

3 years ago