Answer:
<h2>
![\huge \colorbox{blue}{65}](https://tex.z-dn.net/?f=%5Chuge%20%5Ccolorbox%7Bblue%7D%7B65%7D)
</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
order of PEMDAS
- parentheses
- exponent
- multiplication or
- division
- addition or
- substraction
<h3>let's solve:</h3>
simplify multiplication:
![\displaystyle \: \sqrt{ {65}^{2} }](https://tex.z-dn.net/?f=%20%20%5Cdisplaystyle%20%5C%3A%20%20%5Csqrt%7B%20%7B65%7D%5E%7B2%7D%20%7D%20)
use
to simplify:
![\displaystyle \: = {65}^{2 \times \frac{1}{2} } \\ = {65}^{ \cancel{ \: 2 }\times \frac{1}{ \cancel{ \: 2}} } \\ = {65}^{1}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5C%3A%20%20%3D%20%20%7B65%7D%5E%7B2%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%5C%5C%20%20%20%3D%20%7B65%7D%5E%7B%20%5Ccancel%7B%20%5C%3A%202%20%7D%5Ctimes%20%20%5Cfrac%7B1%7D%7B%20%5Ccancel%7B%20%5C%3A%202%7D%7D%20%7D%20%20%5C%5C%20%20%20%3D%20%7B65%7D%5E%7B1%7D%20)
as we know x¹=x
therefore our final answer is
- <em><u>6</u></em><em><u>5</u></em>
Answer:
2v^1 - 2^(18v+1) + 5 ^ 2v +5
Step-by-step explanation:
2v-4^9v+5^2v-4^9v+5
Combine like terms
2v - 4 ^ 9v - 4 ^ 9v + 5 ^ 2v+5
We know a^b - a^b = 2 a^b
2v - 2*4^9v + 5 ^ 2v+5
Rewriting 4 as 2^2 and v as v^1
2v^1 - 2 * 2^2^9v + 5 ^ 2v+5
We know that a^b^c = a^ b*c
2v^1 - 2 * 2^18v + 5 ^ 2v+5
2v^1 - 2^1 * 2^18v + 5 ^ 2v+5
We know that a^1 * a^b = a^ b+1
2v^1 - 2^(18v+1) + 5 ^ 2v+5
<h2>
Answer:</h2>
The final image is:
![\boxed{W''(3,8)}](https://tex.z-dn.net/?f=%5Cboxed%7BW%27%27%283%2C8%29%7D)
<h2>
Explanation:</h2>
Here we have two rules. The first one is a reflection across the y-axis and the second one is a translation. Let's apply these rules in two steps:
First rule:
Reflection across the y-axis:
![(x,y)\rightarrow (-x,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Crightarrow%20%28-x%2Cy%29)
By following this rule, you must multiply the x-coordinate of the point by -1. So here we reflect point W. Then:
![W'(-1,6)](https://tex.z-dn.net/?f=W%27%28-1%2C6%29)
Second rule:
![T(x+4,y+2)](https://tex.z-dn.net/?f=T%28x%2B4%2Cy%2B2%29)
This transformation shift each point 4 units to the right and 2 units up. Here we shift point W' that was previously transformed. Then:
![W''(x,y)=W''(-1+4,6+2) \\ \\ \boxed{W''(x,y)=W''(3,8)}](https://tex.z-dn.net/?f=W%27%27%28x%2Cy%29%3DW%27%27%28-1%2B4%2C6%2B2%29%20%5C%5C%20%5C%5C%20%5Cboxed%7BW%27%27%28x%2Cy%29%3DW%27%27%283%2C8%29%7D)
I don't know about estimate but the answer is 7 7/8 hours
25a + 5b - 13
5(5a + b) - 13 is your answer
using the distributive property, we can distribute 5 to all terms within the parenthesis:
5(5a + b) - 13 = 25a + 5b - 13
5(5a) = 25a
5(b) = 5b
25a + 5b - 13 = 25a + 5b - 13 (True)
hope this helps