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vekshin1
2 years ago
12

Write a function g whose graph represents a reflection in the x-axis of the graph of f(x)=1/2x−3.

Mathematics
2 answers:
Ede4ka [16]2 years ago
8 0
G(x) = -1/2 - 3
(I'm not sure)
11Alexandr11 [23.1K]2 years ago
7 0
Help im doing the same thing



step by step
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A=8, b=5, C=90 degree; Find c, A, and B<br><br> This is for the law of sine and cosine
brilliants [131]

Answer:

• c = √89 ≈ 9.434

• A = arcsin(8/√89) ≈ 57.995°

• B = arcsin(5/√89) ≈ 32.005°

Step-by-step explanation:

By the law of cosines, ...

c² = a² + b² -2ab·cos(C)

Since c=90°, cos(C) = 0 and this reduces to the Pythagorean theorem for this right triangle.

c = √(8² +5²) = √89 ≈ 9.434

Then by the law of sines (or the definition of the sine of an angle), ...

sin(A) = a/c·sin(C) = a/c = 8/√89

A = arcsin(8/√89) ≈ 57.995°

sin(B) = b/c·sin(C) = b/c = 5/√89

B = arcsin(5/√89) ≈ 32.005°

6 0
3 years ago
Brad wants the buy flowers for his friend with 27$. the daises are 1$ each and the roses 3$ each. He buys 3 more daises more tha
Alona [7]
3$ x 6 roses = 18$
1$ x  9 daisies = 9$

18 + 9 = 27$

Answer. 6 roses
8 0
3 years ago
Find f if f′(x)=2x−3/x^4, x&gt;0 and f(1)=2.
slavikrds [6]
f'(x)=2x-\dfrac3{x^4}
\displaystyle\int f'(x)\,\mathrm dx=\int\left(2x-\frac3{x^4}\right)\,\mathrm dx
f(x)=x^2+\dfrac1{x^3}+C

Given that f(1)=2, we get

2=1^2+\dfrac1{1^3}+C
2=2+C
\implies C=2

so that

f(x)=x^2+\dfrac1{x^3}
8 0
3 years ago
What are the domain and range of f(x) = 4* – 8?
White raven [17]

Answer:

domain: {x | x is a real number}

range: {y l y> -8}

Step-by-step explanation:

f(x) = 4x² – 8 is a parabola, a U shape.

Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.

y > -8  because the minimum is -8.

Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.

Quadratic standard form:

f(x) = ax² + bx + c

"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.

"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.

"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.

7 0
2 years ago
Solve for x<br><br> Pls help me again. :(
Alexus [3.1K]

Step-by-step explanation:

80+60+x+51= 180

191+x= 180

x= -11

4 0
3 years ago
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