Answer:
a) 1170
b) 35%
c) 630
Step-by-step explanation:
We have the rational expression
![\frac{2x^{5}-6x^{2}+4x4y}{2x}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%5E%7B5%7D-6x%5E%7B2%7D%2B4x4y%7D%7B2x%7D%20)
; to simplify it, we are going to try to find a common factor in the numerator, and, if we are luckily, that common factor will get rid of the denominator
![2x](https://tex.z-dn.net/?f=2x)
.
Notice that in the denominator all the numbers are divisible by two, so 2 is part of our common factor; also, all the terms have the variable
![x](https://tex.z-dn.net/?f=x)
, and the least exponent of that variable is 1, so
![x](https://tex.z-dn.net/?f=x)
will be the other part of our common factor. Lets put the two parts of our common factor together to get
![2x](https://tex.z-dn.net/?f=2x)
.
Now that we have our common factor, we can rewrite our numerator as follows:
![\frac{2x(x^{5}-6x+2(2y)}{2x}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%28x%5E%7B5%7D-6x%2B2%282y%29%7D%7B2x%7D%20)
We are luckily, we have
![2x](https://tex.z-dn.net/?f=2x)
in both numerator and denominator, so we can cancel those out:
![x^{5}-6x+2(2y)](https://tex.z-dn.net/?f=x%5E%7B5%7D-6x%2B2%282y%29)
![x^5-6x+4y](https://tex.z-dn.net/?f=x%5E5-6x%2B4y)
We can conclude that the simplified version of our rational function is
![x^{5}-6x+4y](https://tex.z-dn.net/?f=x%5E%7B5%7D-6x%2B4y)
.
Answer:
![\large\boxed{\begin{array}{c|c|c|c}Length:&4cm&2cm&8cm\\Width:&6cm&12cm&3cm\\Height:&9cm&9cm&9cm\end{array}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7Cc%7Cc%7Cc%7DLength%3A%264cm%262cm%268cm%5C%5CWidth%3A%266cm%2612cm%263cm%5C%5CHeight%3A%269cm%269cm%269cm%5Cend%7Barray%7D%7D)
Step-by-step explanation:
The formula of a volume of a cube with side length a:
![V=a^3](https://tex.z-dn.net/?f=V%3Da%5E3)
We have a = 6cm. Substitute:
![V=6^3=216\ cm^3](https://tex.z-dn.net/?f=V%3D6%5E3%3D216%5C%20cm%5E3)
![\begin{array}{c|c}216&2\\108&2\\54&2\\27&3\\9&3\\3&3\\1\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7D216%262%5C%5C108%262%5C%5C54%262%5C%5C27%263%5C%5C9%263%5C%5C3%263%5C%5C1%5Cend%7Barray%7D)
![216=2\cdot2\cdot2\cdot3\cdot3\cdot3=(2\cdot2)\cdot(2\cdot3)\cdot(3\cdot3)=4\cdot6\cdot9\\\\216=2\cdot2\cdot2\cdot3\cdot3\cdot3=2\cdot(2\cdot2\cdot3)\cdot(3\cdot3)=2\cdot12\cdot9\\\\216=2\cdot2\cdot2\cdot3\cdot3\cdot3=(2\cdot2\cdot2)\cdot3\cdot(3\cdot3)=8\cdot3\cdot9\\\vdots](https://tex.z-dn.net/?f=216%3D2%5Ccdot2%5Ccdot2%5Ccdot3%5Ccdot3%5Ccdot3%3D%282%5Ccdot2%29%5Ccdot%282%5Ccdot3%29%5Ccdot%283%5Ccdot3%29%3D4%5Ccdot6%5Ccdot9%5C%5C%5C%5C216%3D2%5Ccdot2%5Ccdot2%5Ccdot3%5Ccdot3%5Ccdot3%3D2%5Ccdot%282%5Ccdot2%5Ccdot3%29%5Ccdot%283%5Ccdot3%29%3D2%5Ccdot12%5Ccdot9%5C%5C%5C%5C216%3D2%5Ccdot2%5Ccdot2%5Ccdot3%5Ccdot3%5Ccdot3%3D%282%5Ccdot2%5Ccdot2%29%5Ccdot3%5Ccdot%283%5Ccdot3%29%3D8%5Ccdot3%5Ccdot9%5C%5C%5Cvdots)
So here's the solution to the problem:
Calculate the average sell:
1,700 * $25 = $42,500 (revenue)
And if the Opera House wants to increase their revenue:
The price of a ticket will be:
$25 - x (where x is the number of 1-dollar decreases)
The number of tickets in total:
1,700 + 200x
Therefore the equation is:
(1,700 +200x) * ( 25 - x ) = 55,000
We can also solve this equation, but the solutions are not whole numbers.
x 1 = 5.89 and x 2 =10.6
For x = 6 (6 times 1 - dollar decreases):
( 1,700 + 200 * 6 ) * ( 25 - 6 ) = ( 1,700 + 1,200 ) * 18
=2,900 *19 = 55,100 (we will yield the revenue over $55,000)
Answer:
Step-by-step explanation: If Canada(C) is 32,000,000 and America is A and C x 10 = A then 32,000,000 x 10 = A
And to multiply any whole number by 10 you just add a zero to the end so
320,000,000 is the answer which is pronounced "Three hundred twenty million" And there is 7 zeros in the answer
hope this helps mark me brainliest