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3 years ago

What is the measure of angle K? (5x+10) (6x-1)

Mathematics

1 answer:

frutty [35]3 years ago

6 0

30x2 - 5x + 60x - 10
30x2 + 55x -10

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How do I know if two ratios are equal to make a proportion

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One way to see if two ratios are proportional is to write them as fractions and then reduce them. If the reduced fractions are the same, your ratios are proportional.

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3 years ago

Pls help me on this pofavor

Elanso [62]

You are right: the graph does not represent a proportion, because it does not go thru the origin.

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3 years ago

Help with Math PLZ (Questions in screenshot)

-Dominant- [34]

1.) Let's say that the circle on the graph below represents x. The arrow is pointing to all the numbers greater than x, which happens to be on -2. If it points right, this means that x can equal to any number greater than -2. So your answer is x > -2.

2.) For inequalities such as these, you can simplify just like what you do for normal equations. Let's isolate x.

$x - 7 > 10$

--> $x > 10 + 7$

---> $x > 17$

3.) $3x \leq 21$

--> $\frac{3x}{3} \leq \frac{21}{3}$

---> $x \leq 7$

4.) $5a - 2 < 18$

--> $5a < 18 + 2$

---> $5a < 20$

----> $\frac{5a}{5} < \frac{20}{5}$

-----> $a < 4$

5.) $2t + 8 \geq -4(t + 1)$

--> $2t + 8 \geq -4t - 4$

---> $2t + 4t \geq -8 - 4$

----> $6t \geq -12$

-----> $t \geq -2$

7 0

3 years ago

Help me with the part b!

ra1l [238]

Average speed = (distance final - distance initial)/(time final - time initial)
Average speed = (30-0)km /(100 -0)min = 3/10 km/min

3/10 km/min *60 min/1 h = 180/10 km/h= 18 km/h

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7Bw%7D%7B3%7D%20" id="TexFormula1" ti

ElenaW [278]

Answer: $\bold{w=\dfrac{6y-3}{2}}$

<u>Step-by-step explanation:</u>

Isolate w by performing the following steps

Multiply by 6 on both sides to clear the denominator
Subtract 3 from both sides
Divide both sides by 2

$y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}$

5 0

3 years ago