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elena-s [515]
3 years ago
6

Find the surface area of the triangular prism (above) using its net (below).

Mathematics
2 answers:
Georgia [21]3 years ago
4 0

Answer:

the surface area of the prisim is 136

Marianna [84]3 years ago
3 0

Answer: The surface area is 96

Step-by-step explanation:

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Here are some questions that need answering:<br> thnx!
ipn [44]

Answer:

it wil be 96

Step-by-step explanation:

85 88 and 97 are all numbers that contributet to the exponentialalty ogf this number 96

5 0
2 years ago
Read 2 more answers
What's the LCM of 3,4,6,and8
Makovka662 [10]
The LCM (least common denominator) of 3, 4, 6 and 8 is...
24
4 0
2 years ago
1. A line passes through the points (–4, –6) and (8, 4) a. Use point-slope form to write the equation of the line that is perpen
Ainat [17]

Answer:

I just know the formula for slope is y2-y1/x2-x1

Step-by-step explanation:

6 0
3 years ago
in a survey, 27% of people chose salads over a meat dish. In all, 81 people chose salads. How many people were in the survey?
adelina 88 [10]
Number of people that chose salad = 81
Percentage of people that chose salad over meat dish = 27%
Let us assume the number of people on the survey = x
Then
27% * x = 81
(27/100) * x = 81
27x = 81 * 100
27x = 8100
x = 8100/27
   = 300
So a total of 300 people participated in the survey.I hope the procedure is clear enough for you to understand. Based on this method you can always solve similar types of problems without requiring any kind of help from outside.
6 0
3 years ago
Read 2 more answers
Among the four northwestern states, Washington has 51% of the total population, Oregon has 30%, Idaho has 11%, and Montana has 8
morpeh [17]

Answer:

Step-by-step explanation:

H₀ : The distribution of the sample agrees with the population distribution.

H₁ : the distribution of the does not agree with the population distribution.

Using the  Chi-square test statistics

we will compute the expected frequencies

Now expected frequency for Washington will be

Fe = Npi = 1000×51% = 5100

expected frequency for Oregon

Fe = Npi = 1000×30% = 300

expected frequency for Idaho

Fe = Npi = 1000×11% = 110

expected frequency for  Montana

Fe = Npi = 1000×8% = 80

The Chi=square test statistics is;

x² = ∑ [ (Fo - Fe)² / Fe )

now we substitute

Given our Fo ( 450 in Washington, 340 in Oregon, 150 in Idaho, and 60 in Montana) from the question

x² =  (450-510)²/510 + (340-300)²/300 + (150-110)²/110 + (60-80)²/80

x²= 31.9376

so the chi-square test statistics is 31.9376

Now the chi-square critical value

first we compute for degree of freedom

d.f = k -1 = 4 - 1 = 3

So from the critical value table, degree of freedom 3 and significance level 0.05,

the chi-square critical value is 7.8147

Therefore chi-square test statistics 31.9376 is greater than the chi-square critical value 7.8147, so NULL HYPOTHESIS IS REJECTED at 5% significance.

There is sufficient evidence to warrant rejection  of the claim that the distribution of the sample agrees with the distribution of the state populations.

3 0
3 years ago
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