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DerKrebs [107]
3 years ago
12

Geometry help. Inscribing circle help and constructing lines.

Mathematics
1 answer:
prohojiy [21]3 years ago
3 0
<h3>1. Inscribe a circle ΔJKL. Identify the point of concurrency that is the center of the circle you drew. </h3>

To inscribe a circle in the attached triangle, we must follow the following steps. The resultant figure is the first one below.

1. Draw the angle bisector of angle JKL. The straight line in the green one.

2. Draw the angle bisector of angle KLJ. The straight line in the blue one.

3. Draw point D at these two lines.

4. Draw a line through point D perpendicular to side JK. The straight line in the red one.

5. Mark point G at the red line and side JK.

6. Draw a circle with center at D (point of concurrency) and a radius of DG.


<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>

To circumscribe a circle in the attached triangle, we must follow the following steps:

1. Draw the perpendicular bisector of the side FG. The straight line in the red one. The resultant figure is the second one below.

2. Draw the perpendicular bisector of the side GH. The straight line in the blue one.

3. The center of the circle is the intersection of these two lines

4. Draw a circle with center at D (point of concurrency).

<h3>3. Construct the two lines tangents to circle</h3>

A tangent to a circle is a straight line that touches the circle at an only point. If a point A is outside a circle, we can draw two lines that pass through this point and are tangent to the circle at two different points each. So this is shown in the third figure. Lines red and blue are tangent to the circle at two different points.

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1. Jackson has 75¢ in dimes, d, and nickels, n, in his pocket. Which equation could be solved to find the possible combinations
SpyIntel [72]

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Part 1) Option D 75=10d+5n

Part 2) Option B (4, -2), (0, -1), (-4, 0)

Part 3) Option A 50=2LW

Part 4) Option A Ms. Monti bought 4 adult tickets and 3 children’s tickets

Part 5) Option D The kitten weighed 14 ounces when it was 4 weeks old

Step-by-step explanation:

Part 1)

we know that

1\ dime=\$0.10

1\ nickel=\$0.05

Let

d-------> the number of dimes

n-----> the number of nickels

so

0.10d+0.05n=0.75

Multiply by 100 both sides

10d+5n=75

Part 2)

we have

y=(-\frac{1}{4})x-1

To calculate the solutions of the equation for an x value, substitute the value of x in the equation and find the value of y

For x=4 -----> y=(-\frac{1}{4})(4)-1=-2 ----> (4,-2)

For x=0 -----> y=(-\frac{1}{4})(0)-1=-1 ----> (0,-1)

For x=-4 -----> y=(-\frac{1}{-4})(4)-1=0 ----> (-4,0)

Part 3)

we know that

The perimeter of a rectangle is equal to

P=2(L+W)

we have

P=50\ ft

substitute

50=2(L+W) ------> 50/2=(L+W) -----> 50=2L+2W

Par 4)

Let

x------> the number of adult tickets

y------> the number of children tickets

we have

25x + 15y = 145

The ordered pair (4,3) represent

x=4\ adult\ tickets

y=3\ children\ tickets

therefore

Ms. Monti bought 4 adult tickets and 3 children’s tickets

Part 5)  

Let

x------> the number of weeks after it was born

y-----> the kitten’s weight in ounces

we have

y=2.5x+4  

The ordered pair (4,14) represent

x=4\ weeks

y=14\ ounces

therefore

The kitten weighed 14 ounces when it was 4 weeks old


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3 years ago
Can yall help me with this its an urgent for my final exam
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answer is 6 cm. basically fd is the radius whereas be is the diameter

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