Answer:
Step-by-step explanation:
Answer:
The value of 27, because it’s greater than 26.7 and less than 29.3.
Step-by-step explanation:
You should find the confidence Interval at 95%
The formula to apply is;
C.I= x±z*δ/√n
where C.I is the confidence interval, x is the mean of the sample, z is the z* value from the standard normal distribution for 95% confidence interval, δ is the standard deviation and n is the sample size
Substitute values in the formula
![z*=1.96\\\\](https://tex.z-dn.net/?f=z%2A%3D1.96%5C%5C%5C%5C)
Find δ/√n
![=\frac{5}{\sqrt{60} } =0.64549722436\\\\\\](https://tex.z-dn.net/?f=%3D%5Cfrac%7B5%7D%7B%5Csqrt%7B60%7D%20%7D%20%3D0.64549722436%5C%5C%5C%5C%5C%5C)
Calculate z*δ/√n
![=1.96*0.64549722436=1.2652\\\\\\](https://tex.z-dn.net/?f=%3D1.96%2A0.64549722436%3D1.2652%5C%5C%5C%5C%5C%5C)
C.I= 28±1.2652
Upper limit is = 28+1.2652=29.2625
Lower limit is =28-1.2652=26.7348
Solution
The value 27 is within 95% confidence interval because it is greater than 26.7 and less than 29.3
Answer:
Step-by-step explanation:
what
Answer:
89.44%.
Step-by-step explanation:
Let's work out the probability he misses both throws:
Prob( he misses both throws) = (1-0.78) * ( 1 - 0.52)
= 0.22*0.48
= 0.1056.
So the probability he makes at least one free throw = 1 - 0.1056
= 0.8944.
(It is 1 - 0.1056 because the default of missing both throws is either making one throw on first or second attempt, or making both throws).
3x^2 + 5x + 25
3 (3)^2 + 5(3) + 25
3 (9) + 5(3) + 25
27+ 15 +25
67