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3 years ago

12

Mía desea pintar una pared de su habitación. Ella no dispone de mucho tiempo al día, por lo que cada día pinta una parte de la p

ared. El lunes pintó ⅜ de la pared y el martes ⅛ de la pared. Si el miércoles pintó ¼ de la pared, ¿qué parte de la pared le falta pintar?

1 answer:

Lubov Fominskaja [6]3 years ago

6 0

Well, 1/3 = 428 so that you could get the same thing as 28 75 hours for you to go to school

You might be interested in

1. Let L be a list of numbers in non-decreasing order, and x be a given number. Describe an algorithm that counts the number of

e-lub [12.9K]

Answer:

Algorithm

Start

Int n // To represent the number of array

Input n

Int countsearch = 0

float search

Float [] numbers // To represent an array of non decreasing number

// Input array elements but first Initialise a counter element

Int count = 0, digit

Do

// Check if element to be inserted is the first element

If(count == 0) Then

Input numbers[count]

Else

lbl: Input digit

If(digit > numbers[count-1]) then

numbers[count] = digit

Else

Output "Number must be greater than the previous number"

Goto lbl

Endif

Endif

count = count + 1

While(count<n)

count = 0

// Input element to count

input search

// Begin searching and counting

Do

if(numbers [count] == search)

countsearch = countsearch+1;

End if

While (count < n)

Output count

Program to illustrate the above

// Written in C++

// Comments are used for explanatory purpose

#include<iostream>

using namespace std;

int main()

{

// Variable declaration

float [] numbers;

int n, count;

float num, searchdigit;

cout<<"Number of array elements: ";

cin>> n;

// Enter array element

for(int I = 0; I<n;I++)

{

if(I == 0)

{

cin>>numbers [0]

}

else

{

lbl: cin>>num;

if(num >= numbers [I])

{

numbers [I] = num;

}

else

{

goto lbl;

}

}

// Search for a particular number

int search;

cin>>searchdigit;

for(int I = 0; I<n; I++)

{

if(numbers[I] == searchdigit

search++

}

}

// Print result

cout<<search;

return 0;

}

8 0

3 years ago

How to solve this problem?:

kipiarov [429]

What problem i dont see nun

8 0

3 years ago

Read 2 more answers

Write the direct variation function given that y varies directly with x, and y = 1.5 when x = 5.

Cloud [144]

Answer:

y=0.3x

Step-by-step explanation:

Formula = $K=\frac{y}{x}$

y α x

y = kx

Where k is the constant of proportionality.

When y = 1.5; x = 5;

We substitute these known values in the equation,

y = kx

1.5 = k5

Dividing both sides of the equation by 5 to find the value for k, we have

1.5/5= k0.3/5

Therefore,

K = 0.3

Having found the value of k,

We substitute this value into the relationship

y = kx

Therefore we have,

y = 0.3x.

The direct variation function is therefore,

y = 0.3x.

[RevyBreeze]

4 0

2 years ago

Help me with this one.......

NemiM [27]

The rachos were sold are 6
because ratio of them at the begining = 3/4
after selling some popcorns, ratio of them still 3/4
they sold 8 popcorns mean 3/4 = ?rachos / 8popcorns sold
the rachos sold = 3*8/4 = 6

4 0

3 years ago

There are 130 m&m's in a bag. there are half as many green as red. the number of blue is equal to the number of red and gree

AleksandrR [38]

Let x = red
Let 0.5x = green
Let (x) + (0.5x) = 1.5x = blue
Let 0.5(1.5x) = 0.75x = yellow
Let 0.75x + 4 = brown

$(x) + (0.5x) + (1.5x) + (0.75x) + (0.75 + 4) = 130$
$x + 0.5x+ 1.5x + 0.75x + 0.75 + 4 = 130$
$4.5x + 4 = 130$
$4.5x = 126$
$x = 28$

Use this value to calculate the other required numbers.
red = 28
green = 0.5x = 0.5(28) = 14
blue = 1.5x = 1.5(28) = 42
yellow = 0.75x = 0.75(28) = 21
brown = 0.75x + 4 = 0.75(28) + 4 = 25

8 0

3 years ago