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Reika [66]
2 years ago
15

If (m+n)^2=m^2+n^2, what is (3^m)^n?

Mathematics
1 answer:
svp [43]2 years ago
4 0

Answer:

(3^m)^n=1

Step-by-step explanation:

(m+n)^2=m^2+n^2\\m^2+2mn+n^2=m^2+n^2\\(m^2+n^2)-(m^2+n^2)+2mn=0\\2mn=0\\This\ equation\ has\ two\ solutions\ : m=0,n=0\\\\But\ either\ way\ will\ result\ in\ the\  same\ answer.\\If\ m=0\ then,\\(3^0)^n\\=1^n\\=1\\\\If\ n=0 \ then,\\(3^m)^0\\=1

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You are given two sides and the included angle. Since you don't have any side and the opposite angle, you must use the law of cosines.

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3 years ago
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