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kicyunya [14]
2 years ago
15

I NEED HELP WITH THIS, SHOW YOUR WORK!!! BRAINLY TO WHOEVER CAN GET IT RIGHT

Mathematics
1 answer:
Karolina [17]2 years ago
6 0

Answer: B and E

I used a calculator, it’s correct

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Solve the inequality 5y+4 ≤ 22-y and graph the solution set on a number line. Please explain how to do it!
gtnhenbr [62]

Answer:

y≤3

Step-by-step explanation:

5y+4≤22−y

<em>Step 1: Simplify both sides of the inequality.</em>

5y+4≤−y+22

<em>Step 2: Add y to both sides.</em>

5y+4+y≤−y+22+y

6y+4≤22

<em>Step 3: Subtract 4 from both sides.</em>

6y+4−4≤22−4

6y≤18

<em>Step 4: Divide both sides by 6.</em>

6y/6≤18/6

y≤3

4 0
2 years ago
Read 2 more answers
Kamala has 2 liter of soup. he pours it into 4 bowls. each bowl gets an equal amount. how many millilitres of soup are in each b
Aleksandr [31]

Answer:

500ml

Step-by-step explanation:

2000 \div 4 = 500

5 0
3 years ago
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HELLLLLPPPP MEEEE
soldi70 [24.7K]
X=11 because u Solve for the first variable in one of the equations, then substitute the result into the other equation.
5 0
2 years ago
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Can anyone tell me how you could describe this answer to the equation?
DanielleElmas [232]

The end behavior of the given polynomial is that as x → -∞ or  x → ∞, then, f(x) → 5

<h3>What is the end behavior of the Polynomial?</h3>

We are given the polynomial;

f(x) = 5x/(x - 25)

Now, we want to find the limits as x → ±∞. Let us rearrange the given polynomial to get; f(x) = 5/(1 - (25/x))

Thus, applying limits we have;'

lim x → ±∞ [5/(1 - (25/x))]

From algebraic limit laws we know that;

If f(x) = k, then;

lim x → +∞ [f(x)] = k

Also, lim x → -∞ [f(x)] = k

Thus, applying limits at infinity to our polynomial gives;

lim x → ±∞ [5/(1 - (25/x))] = 5/(1 - 0) = 5

This is because lim x → ∞ for 1/x is 0.

Thus, f(x) has horizontal asymptotes at y = 5

Thus, we conclude that the end behavior is that as x → -∞ or  x → ∞, then, f(x) → 5

Read more about Polynomial End behavior at; brainly.com/question/20347699

#SPJ1

8 0
1 year ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
2 years ago
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