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Sedaia [141]
3 years ago
10

Which graph shows the solution to this inequality? 3r+2(12r+7) ≤ 5r-8​

Mathematics
2 answers:
KIM [24]3 years ago
7 0
Answer: A
Hope this helps :)
Ilya [14]3 years ago
5 0

Answer:

r ≥ -1. it is A because r is greater than or equal to -1.

I am sorry <u>if</u> I got it wrong.

Step-by-step explanation:

3r+2(12r+7) ≤ 5r-8

27r+14 ≤ 5r-8

I subtract 27r and 5r.

22r+14 ≤ -8

I subtract 14 and -8.

22r ≤ -22

Divide 22 on both side.

r ≥ -1

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6a+5a=-11 whats the breakdown to get the answers
kenny6666 [7]

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8 0
3 years ago
Verify that (cos²a) (2 + tan² a) = 2 - sin² a....<br>​
Sveta_85 [38]

Trigonometric Formula's:

\boxed{\sf \ \sf \sin^2 \theta + \cos^2 \theta = 1}

\boxed{ \sf tan\theta = \frac{sin\theta}{cos\theta} }

Given to verify the following:

\bf (cos^2a) (2 + tan^2 a) = 2 - sin^2 a

\texttt{\underline{rewrite the equation}:}

\rightarrow \sf (cos^2a) (2 + \dfrac{sin^2 a}{cos^2 a} )

\texttt{\underline{apply distributive method}:}

\rightarrow \sf 2 (cos^2a) + (\dfrac{sin^2 a}{cos^2 a} ) (cos^2a)

\texttt{\underline{simplify the following}:}

\rightarrow \sf 2cos^2 a  + sin^2 a

\texttt{\underline{rewrite the equation}:}

\rightarrow \sf 2(1 - sin^2a )  + sin^2 a

\texttt{\underline{distribute inside the parenthesis}:}

\rightarrow \sf 2 - 2sin^2a   + sin^2 a

\texttt{\underline{simplify the following}} :

\rightarrow \sf 2 - sin^2a

Hence, verified the trigonometric identity.

7 0
2 years ago
Read 2 more answers
1.17375 rounded to nearest tenth​
Elden [556K]

Answer:

1.2

Step-by-step explanation:

Since we are rounding it by the tenth, it means we are rounding to the 1st digit to the right of the decimal.

We know 7 is greater then 5 meaning we round up

.1 + .1 is equal to .2 meaning its 1.2

If you still don't understand, I recommend you talk to your teacher

5 0
3 years ago
Read 2 more answers
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