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3 years ago

9

Find the arithmetic series a=2 d=5 n=20 find Sn

1 answer:

diamong [38]3 years ago

4 0

Step-by-step explanation:

Sn=n/2{2a+(n-1)d}

=10(4+95)

=10(99)

=990

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Gemma is creating a histogram based on the table below.

Brilliant_brown [7]

Answer:

25-40

Step-by-step explanation:

Step-by-step explanation: The largest amount of people is 40 the lowest amount is 35 so to maximize the bars you would want the smallest range.

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3 years ago

Find the derivative of f(x) = x/6 at x = -2.

AfilCa [17]

$f'(x_0)=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{x}{6};\ x_0=-2\\\\subtitute\\\\f'(-2)=\lim\limits_{x\to-2}\dfrac{\frac{x}{6}-\frac{-2}{6}}{x-(-2)}=\lim\limits_{x\to-2}\dfrac{\frac{x}{6}+\frac{2}{6}}{x+2}=\lim\limits_{x\to-2}\dfrac{\frac{x+2}{6}}{x+2}\\\\=\lim\limits_{x\to-2}\left(\dfrac{x+2}{6}\cdot\dfrac{1}{x+2}\right)=\lim\limits_{x\to-2}\dfrac{1}{6}=\dfrac{1}{6}$

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3 years ago

On a map, Tampa and Boston are 19 cm apart.

liraira [26]

Answer:

1900 km

Step-by-step explanation:

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4 years ago

Read 2 more answers

Solve for a.<br><br> 4a + 2a − a = 5

vredina [299]

Com blind like terms 4a + 2a =6a -a =5a the divide both sides 5/5 5/5a which = 1

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4 years ago

Find the altitude of triangle whose vertex is a(1,-2) and the equation of the base is X+y=3.

Sophie [7]

Answer:

$2\sqrt {2}$

Step-by-step explanation:

<u>Distance From a Point to a Line</u>

Given a line with an equation :

ax + by + c = 0

And the point $(x_0,y_0)$

The distance from the line to the point is given by

$\displaystyle d=\frac {|ax_{0}+by_{0}+c|}{\sqrt {a^{2}+b^{2}}}$

The triangle has a vertex at (1,-2) and the base lies on the equation

x + y = 3

Rearranging:

x + y - 3 = 0

The altitude of the triangle is the distance from the point to the line.

The values to use in the formula of the distance are: a=1, b=1, c=-3, xo=1, yo=-2:

$\displaystyle d=\frac {|1*1+1*(-2)-3|}{\sqrt {1^{2}+1^{2}}}$

$\displaystyle d=\frac {|1-2-3|}{\sqrt {2}}$

$\displaystyle d=\frac {4}{\sqrt {2}}$

Rationalizing:

$\displaystyle d=\frac {4}{\sqrt {2}}\cdot\frac{\sqrt {2}}{\sqrt {2}}$

$\displaystyle d=2\sqrt {2}$

The altitude of the triangle is $\mathbf{4\sqrt {2}}$

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3 years ago