3 years ago

After completing the square what are the solutions to the quadratic equation below?

Mathematics

1 answer:

KiRa [710]3 years ago

6 0

But Where is rest of Question?

.....

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4x+6<-6<br> Solve for x put steps

chubhunter [2.5K]

First move the constant to the other side causing it to change sides

4x<-6-6

Then calculate the difference (-6-6)

4x<-12

Now divide both sides by 4

X<-3

Then you are left with your answer:

x<-3

Hope this helps! :3

4 0

3 years ago

Read 2 more answers

Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly low, μ- 2σ , and the maximum val

allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

$n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\$

Using the binomial distribution: $\mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186$

In this the maximum value which is significantly low, $\mu-2\sigma$ , and the minimum value which is significantly high, $\mu+2\sigma$ , that is equal to: