K = 4pq^2
k/4p = q^2
0.5(k/p)^1/2 = q
false because half of a diameter is a radius
I wonder what the best way of explaining this is? You could graph the results for each choice. Or you could reason it out.
The first thing you have to do it deal with y = 3. Draw a really crude graph like a set of axis. Make the y values go from -5 to + 5. x for the moment does not matter.
Draw a horizontal line through y = 3 or going through the point (0,3). Now here's the catch and you're going to have to read it very carefully.
Condition One
If a>0 then the graph opens upward and b is going to have to be less than 3. That sentence is an absolute nightmare. Think carefully about what a>0 means. Make it 2 and draw a rough graph opening upward on the crude axis you have drawn. b is the y value of the minimum, so that minimum has to be less than 3. Are there any point like that? The two points where a>0 are C and D.
C
The lowest point that C will hit is 4. That's not good enough. b = 4 is the lowest y value. C is not the answer
D
The lowest point is 3. The graph will just touch y = 3. That's not good enough either. Touching y = 3 does not produce 2 roots. It produces just one.
Condition Two
a < 0 Here the graph opens downward. It means the a<0 and b>3. You need to look at A or B. Which point does that? A has a maximum below 3. It's no good. A is wrong.
So the answer must be B. a<0 and b>3. Right on 2 solutions.
Answer:
The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = 0.00621
Step-by-step explanation:
This is a normal distribution problem
The mean of the sample = The population mean
μₓ = μ = 4 ounces
But the standard deviation of the sample is related to the standard deviation of the population through the relation
σₓ = σ/√n
where n = Sample size = 100
σₓ = 1.2/√100
σₓ = 0.12
The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3)
To do this, we first normalize/standardize the 4.3 ounces
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (4.3 - 4)/0.12 = 2.5
To determine the probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = P(z > 2.5)
We'll use data from the normal probability table for these probabilities
P(x > 4.3) = P(z > 2.5) = 1 - P(z ≤ 2.5) = 1 - 0.99379 = 0.00621
