Answer:
480/(x+60) ≤ 7
Step-by-step explanation:
We can use the relations ...
time = distance/speed
distance = speed×time
speed = distance/time
to write the required inequality any of several ways.
Since the problem is posed in terms of time (7 hours) and an increase in speed (x), we can write the time inequality as ...
480/(60+x) ≤ 7
Multiplying this by the denominator gives us a distance inequality:
7(60+x) ≥ 480 . . . . . . at his desired speed, Neil will go no less than 480 miles in 7 hours
Or, we can write an inequality for the increase in speed directly:
480/7 -60 ≤ x . . . . . . x is at least the difference between the speed of 480 miles in 7 hours and the speed of 60 miles per hour
___
Any of the above inequalities will give the desired value of x.
Find the prime factorization of each value.
21 is 7*3
30 is 3*10 which can be further broken down into 3*2*5
44 is 4*11 which can be further broken down into 2*2*11
What do they share in common?
21 and 30 each have a 3 in common.
Therefore the GCF(21, 30) = 3.
21 and 44 share a 2 in common.
But if we're looking at all three of them together, they share nothing in common.
x = 30
The distributive property says that we need to multiply what's in the brackets by 1/2 (so 1/2*x and 1/2*6) to get the equation 1/2x + 3 = 18.
Then we need to subtract our constant, 3, from boths sides to get 1/2x = 15.
Multiply both sides by two to isolate x and you get x = 30.
Hope this helps! :)
30 CM
0.984252 FT
300.0000096 MM
Answer:
True
Step-by-step explanation:
The year is typically divided into equal different lengths of time. There are, for example, quarters, which divide the year by 4, i. e., in 4 periods of 3 months each. Other example are semesters, in this case, the year is divided into 2 periods of 6 months each. Taking this into account, an interest calculated on a balance every three months is compounded quarterly.
