Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula
where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,
or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
15 cm
Step-by-step explanation:
Given that :
Reading at one end, initial reading = 3.5 cm
Reading at the other end, final reading = 18.5 cm
Length of needle :
Final Reading - Initial reading
18.5cm - 3.5cm
= 15cm
Answer:
The initial value in the word problem is the output value when input value is set to zero.
Step-by-step explanation:
- In the question, it is given that a problem uses a linear function.
- It is required to explain how to interpret the initial value in a word problem.
- In order to find the initial value in a world problem, find the output value when input value is set to zero.
- If the initial value is marked as b for a linear function f(x), find it as follow,
What are the lower and upper quartiles of this data 122,164,71,98,84,147,114,111,98,85,104,71,77
RSB [31]
Lower quartile = 80.5
Upper quartile = 118
