3 years ago

PLEASE HELP, MUST ANSWER NOW!!!!!!!!!!

Mathematics

2 answers:

klasskru [66]3 years ago

5 0

Answer:

Step-by-step explanation:

In-s [12.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

( it might be wrong pls dont report me just let me kno y its wrong )

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a 23 gram sample of a substance thats a by-product of fireworks has a K-value of .13. whats the substances half life in days

nata0808 [166]

Given:
Initial mass, m₀ = 23 g
Decay constant, k = 0.13

Exponential decay obeys the equation
$m(t)=m_{0} e^{-kt}$
where t = time, days

For half life, the mass is m = m₀/2.
Therefore
$e^{-0.13t} = \frac{1}{2} \\ -0.13t = ln(0.5)\\t= \frac{ln(0.5)}{-0.13} =5.33$

Answer: The half life is 5.33 days

3 0

3 years ago

Read 2 more answers

If y varies directly as the square root of x and y = 8 when x = 36, find the value of y when x = 144. y =

Wittaler [7]

Answer:

y=32

Step-by-step explanation:

cross multiply

36/4 *144/y

144*8/36

=1152/36