In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Answer:
All you need to remember is the rules
Step-by-step explanation:
Let us remember
a to the m power x a to the nth power is = a to the m+n power. (add the exponents)
And
a to the m power ÷ a to the nth power is = a to the m-n power. (subtract the exponents) So
14 to the -4 power x 14 to the 7 power= 14 to the -4+7 which is equal to 14 to the 3rd power
Reciprocal
Explanation:
I know what I know and this is one of those things
Answer:
that can help because all you need to remember is that the sum of the angles in a triangle is half of the sum of the angles that add up in a quadrilateral.
