Answer:
a) This is an Observational Study because in this kind of study investigators observe subjects and measure variables of interest without assigning treatments to the subjects. Here, the Gilham et al. (2005) studied two different groups where no treatment or intervention was done. These groups were independent of each other.
b) proportions of children with significant social activity in children with acute lymphoblastic leukemia = 1020/1272 = 0.80
proportions of children with significant social activity in children without acute lymphoblastic leukemia = 5343/6238 = 0.86
c) Odds ratio can be calculated using the following formula:
OR= \frac{a/b}{c/d}
where: a - Number in exposed group with positive outcome(here this means number of children with significant social activity associated with acute lymphoblastic leukemia)
b- Number of children without social activity having with acute lymphoblastic leukemia
c- Number of children with social activity having without acute lymphoblastic leukemia
d- Number of children without social activity having without acute lymphoblastic leukemia
OR= \frac{1020/252}{5343/895}
OR= 0.6780
d) The 95% confidence interval of this Odds Ratio is 0.5807 to 0.7917.
e) Since the odds ratio lies in this confidence interval indicate that the amount of social activity is associated with acute lymphoblastic leukemia. The children with more social activity have a higher occurrence of acute lymphoblastic leukemia.
Answer:
8
Step-by-step explanation:
f(x) = (x+2)(x-2)
Substituting x=1 into f(x):
f(1) = 3*-1
= -3
Since -2 & 2 touch the x-axis, 1 has a negative y value, 2 has a y value of 0, and all values from 2, are positive.
Hence,
3, 4, 5, 6, 7, 8, 9, 10 are all positive. Therefore, the answer is 8
This can be confirmed with a graph, as attached below.
<em>Feel free to mark this as brainliest! :D</em>
Peter has 4 friends. He invited them to his home. He ordered a pizza of his favorite and made it into 5 slices.
Few minutes later, one of his friends Smith came and they enjoyed one slice of pizza each.
Now, the question is what portion of the pizza left for his remaining friends?
Answer :
Peter made the pizza into 5 pieces.
So, 
Peter and Smith had 
th of the pizza each.
So, the remaining portion = 
Answer:
For h = 0.1 y(1) = 2.5937
For h =0.05. y(2) = 2.6533
Step-by-step explanation:
Find attached below extensive solution to problem
