The given inequality is y ≥ |x + 2| -3.
This inequality may be written two ways:
(a) y ≥ x + 2 - 3
or
y ≥ x - 1
(b) y ≥ -x -2 - 3
or
y ≥ -x - 5
A graph of the inequality is shown below. The shaded region satisfies the inequality.
Answer: A shaded region above a solid boundary line.
Answer:
Step-by-step explanation:
In a rectangle, diagonals are equal and bisect each other
BE = AE
6x - 5 = 2x + 7
6x - 2x - 5 = 7
4x - 5 = 7
4x = 7 + 5
4x = 12
x = 12/4
x = 3
AE = 2x + 7
= 2*3 + 7
= 6 + 7
AE = 13
AC = 13 + 13
AC = 26
m∠EBC = 50
In rectangle, each angle is 90
m∠ABE + m∠EBC = 90
m∠ABE + 50 = 90
m∠ABE = 90 - 50
m∠ABE = 40
In rectangle, AB // DC and DB transversal
m∠ECD = m∠ABE { alternate interior angles}
m∠ECD = 40
I'm pretty sure both B and C equal 12 as well
Since the triangle equals 180 and the angels are all congruent