Answer:
This is an Exponential Decay
Step-by-step explanation:
A = 1200(0.85)⁶
The above expression is an Exponential Decay because 0.85 is less than 1
The formula for Exponential Decay
= y = a (1 - r)^t
We equate both equation together
Where
a = 1200
1 - r = 0.85
t = 6
Solving for r
1 - r = 0.85
r = 1 - 0.85
r = 0.15
Converting to Percentage
r = 15% decay rate
Answer:
last test grade=x x ≥ 79 so 79%
Step-by-step explanation:
(84/5)+(88/5)+(95/5)+(104/5)+(x/5) ≥ 90
Simplify: (371/5)+(x/5) ≥ 90
Subtract (371/5) from both sides
Then you have (x/5) ≥ (79/5)
Then multiply both sides by 5 and you have x ≥ 79
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Answer:
Step-by-step explanation:
First you do the parentheses so the -3 x 8n= -24 and -3 x -5= 15
so it will look like this. -24n+15-2n=8n-21
Now combine like terms the -24n-2n.
-26n+15=8n-21 now subtract 8n now it will look like this
-34n+15=-21 now -15 from -21
-34n=-36
now if you want n by its self divide -34 and -36
Answer:
D) 0 = 2(x + 5)(x + 3)
Step-by-step explanation:
Which of the following quadratic equations has no solution?
We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.
A) 0 = −2(x − 5)2 + 3
0 = -2(x - 5) × 5
0 = (-2x + 10) × 5
0 = -10x + 50
10x = 50
x = 50/10
x = 5
Option A has a solution of 5
B) 0 = −2(x − 5)(x + 3)
Take each of the factors and equate them to zero
-2 = 0
= 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
Option B has a solution by one of its factors as a positive value of 5
C) 0 = 2(x − 5)2 + 3
0 = 2(x - 5) × 5
0 = (2x -10) × 5
0 = 10x -50
-10x = -50
x = -50/-10
x = 5
Option C has a solution of 5
D) 0 = 2(x + 5)(x + 3)
Take each of the factors and equate to zero
0 = 2
= 0
x + 5 = 0
x = -5
x + 3 = 0
x = -3
For option D, all the values of x are 0, or negative values of -5 and -3.
Therefore the Quadratic Equation for option D has no solution.
