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3 years ago

Please help me iv been having trouble with this problem

Mathematics

2 answers:

AleksAgata [21]3 years ago

7 0

Please check attachment

kupik [55]3 years ago

6 0

Answer:

9/10 is located the line before 1

2 1/5 is located two lines after 2

i think

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solve the inequality below. Use the drop-down menus to describe the solution and its graph -7x+13>41

3241004551 [841]

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-7x + 13 > 41

- 13

-7x > 28

/ -7

x < -4

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7 0

3 years ago

HELP ME PLEASE!! Word problem, what's wrong? explain.

dmitriy555 [2]

Answer:

She made a mistake in Step 7.

Step-by-step explanation:

Step 1 through 6 are correct. Only from Step 6 to Step 7 the problem comes in: both sides of the equation are multiplied by x, however the x on the left side, by error, becomes 1. The correct state in Step 7 should look like this:

$x(\frac{1}{2}P-x)=256$

8 0

3 years ago

Two ninths of 540 students at east side middle school are in chorus. 3/4 of chorus members are girls. 2/5 of the girls in chorus

lisov135 [29]

2/9 • 3/4 • 2/5 = 1/15
1/15 of of the students are girl sopranos in chorus.

5 0

3 years ago

How many times greater is 3.8 x 105 than 1.9 X 1022 2 20 200 2000

PilotLPTM [1.2K]

Step-by-step explanation:

there must be something wrong with your text.

what we can see is

3.8 × 105

and

1.9 × 1022

the true answer for these values has nothing to do with the 4 answer options.

maybe you meant

1.9 × 10.5 ?

because that answer would be 20.

but first working with the presented numbers :

3.8 × 105 = 399

1.9 × 1022 = 1941.8

so, the second number is actually much bigger than the first number.

but if it is

1.9 × 10.5 = 19.95

that works.

and we can either use the calculator to calculate

399 / 19.95 = 20

or we can simply look at the factor changes of the multiplication terms.

3.8 = 1.9 × 2

105 = 10.5 × 10

so, the multiplication product of the two larger numbers is then 2×10=20 times larger than the product of the 2 smaller numbers.

7 0

3 years ago

Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu

dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

$d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\$ Substituting the values

$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$

So the total distance travelled is 1031 feet.

4 0

3 years ago