Answer:
(a) AC = 12.565 m
(b) bearing of C from A is 90°
(c) BT = 9.373 m
Step-by-step explanation:
(a) extend North line down & perpendicular to AC.
Call that perpendicular intersection "P".
∠BAC = 90° - 53° = 37°
cos 37° = AP/15
0.7986 = AP/15
AP = 11.979 m
∠PNC = 180° - 161° = 19°
∠BCP = 90° - 19° = 71°
18 cm = 0.18 m (red flag note: 18 cm looks very out of scale for the picture)
cos 71° = CP/0.18
0.3256 = CP/0.18
CP = 0.586 m
AC = 11.979 + 0.586 = 12.565 m
(b) The bearing to C from A is 90°
(c) tan 58° = 15/x
1.6003 = 15/x
x = 9.373 m
Answer:
75π
Step-by-step explanation:
The formula for volume of a cone is 
. If you substitute 5 into the radius and 9 into the height, you get 
Answer:
To solve this, we will need to use log properties. We know that subtracting two log equations gives us:
If log base 10 equals 2, we know that 
equals 100. We can solve this by:
= 100
5x³=100x²
x³= 20x²
x³-20x²=0
x²(x-20)=0
Thus, the answer is x=20.
Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
3x - 5y = - 2 → (1)
2x + y = 3 → (2)
Multiply (2) by 5 will eliminate y when added to (1), that is
10x + 5y = 15 → (3)
Add (1) and (3) term by term
(3x + 10x) + (- 5y + 5y) = (- 2 + 15)
13x = 13 ( divide both sides by 13 )
x = 1
Substitute x = 1 into (2) for corresponding value of y
2 + y = 3 ⇒ y = 3 - 2 = 1
Solution is (1, 1)
Twice = multiply by 2
Sum = addition = +
Now that you know those things, all you have to do is plug the numbers in:
2(x + 20)
