Answer:
Step-by-step explanation: you would first subtract the 3 from 9 for a basic fee. And after you would decide 6 by .40 and you would end up traveling 15km
Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
Answer:


An we can use the normal standard table and the following difference and we got this result:

Step-by-step explanation:
Assuming this statement to complete the problem "with a standard deviation 5 mpg"
We have the following info given:
represent the mean
represent the deviation
We have a sample size of n = 54 and we want to find this probability:

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

And we can use the z score formula given by:

And replacing we got:


An we can use the normal standard table and the following difference and we got this result:

Answer:
C. x 0 1 2 p(x) 0.35 0.60 0.05
Step-by-step explanation:
50% chance of survival
Let:
x = older eaglet survive
y = younger eaglet survive
Hence,
P(x = 0) (none of the eaglet survive)
P(x = 1) (only one survive)
P(x = 2) (both survive)
P(x) = 0.5
P(x') = 1 - 0.5 = 0.5
P(x n y) = 0.5 * 0.1 = 0.05 ( both survive)
P(only one survive)
P(y n x') + p(y' n x)
(0.5 * 0.3) + (0.5 * (1 - 0.1))
0.15 + 0.45 = 0.6
P(none survives)
1 - (0.60 + 0.05)
= 0.35
X _______ 0 ______ 1 ______ 2
P(x) ____ 0.35 ____ 0.60 ___ 0.05