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KIM [24]
3 years ago
13

2(x+1)=3x-x+2 help fast and show work please

Mathematics
1 answer:
Stells [14]3 years ago
5 0

Answer:

0=0

Step-by-step explanation:

2(x+1)=3x-x+2\\\\\mathrm{Add\:similar\:elements:}\:3x-x=2x\\2\left(x+1\right)=2x+2\\\\\mathrm{Expand\:}2\left(x+1\right):\quad 2x+2\\2x+2=2x+2\\\\\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\2x+2-2=2x+2-2\\\\Simplify\\2x=2x\\\\\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}\\2x-2x=2x-2x\\\\Simplify\\0=0\\\\\mathrm{True\:for\:all}\:x

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Find the non-extraneous solutions of the square root of the quantity of x plus 3 minus 4 equals x minus 1.
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7 0
3 years ago
Read 2 more answers
Show that (2, 1) is a solution of the system of equations. x + 3y = 5, y = –x + 3 Substitute (2, 1) into x + 3y = 5 to get . Sim
Natalka [10]

I am not sure if I understand the question that clearly but if what I think is correct is that you need to prove that 2 and 1 are a system of equations for the following equations so this is how you do that:

With the coordinates (2,1) 2 will be x and 1 will be y because when dealing with coordinates (x,y) is how they are set up.

Next you substitute into the equations and solve:

(2) + 3(1) = 5 and 1 = -(2)+3

So now you find if the equations are true

2 + 3 = 5 so (2,1) is a solution for this equation

-2 + 3 = 1 so (2,1) is also a solution for this equation

So in conclusion (2,1) is a solution of the system of equations

Hope this helps :)

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3 years ago
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