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Masja [62]
3 years ago
7

Based only on the information given in the diagram, it is guaranteed that

Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer:

True

Step-by-step explanation:

Given

In JKL, we have:

\angle J = 27

\angle K = 90

In WXY, we have:

\angle Y = 63

\angle X = 90

Required

Is JKL ~ WXY?

In both triangles, we already have one similar angle (90)

Next, is to determine the third angles in both triangles.

In JKL

\angle J + \angle K + \angle L = 180

We have that:

\angle J = 27 and \angle K = 90

The expression becomes:

27 + 90 + \angle L = 180

117 + \angle L = 180

\angle L = 180-117

\angle L = 63

In WXY

\angle W + \angle X + \angle Y = 180

We have that:

\angle Y = 63 and \angle X = 90

The expression becomes:

\angle W + 63 + 90 = 180

\angle W + 153 = 180

\angle W = 180-153

\angle W = 27

The three angles in JKL are:

\angle J = 27    \angle K = 90   \angle L = 63

The three angles in WXY are:

\angle W = 27   \angle X = 90   \angle Y = 63

<em>By comparing the angles, we can conclude that  both triangles are similar because of AAA postulate (Angle-Angle-Angle)</em>

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Vinvika [58]
<h3>Answer:   0.5</h3>

========================================================

Explanation:

The ultimate goal is to find the value for lowercase c, or find the length of side c. So we'll use the portion sin(C)/c as part of the law of sines.

We don't know the value of lowercase 'a', so we'll ignore the sin(A)/a portion.

This leaves sin(B)/b

We see that one side is 2 cm long, so this means b = 2. The angle opposite this is 105 degrees, so B = 105.

The angle opposite side c is 15 degrees, so C = 15.

The lowercase letters represent side lengths, while the uppercase letters are angles.

--------------------------

We have enough to apply the law of sines to solve for side c.

sin(B)/b = sin(C)/c

sin(105)/2 = sin(15)/c

c*sin(105) = 2*sin(15) ............. cross multiply

c = 2*sin(15)/sin(105) .............. dividing both sides by sin(105)

c = 0.53589838486224

c = 0.5

Side c is roughly 0.5 cm long.

Make sure your calculator is in degree mode.

6 0
3 years ago
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A car is traveling up a steep ramp to a parking garage.the ramp is 445 feet long and rises a vertical distance of 80 feet. What
Alecsey [184]
With the information provided in the problem, we can create a right triangle with the ramp as its hypotenuse, and  the vertical rise as its opposite side from its angle of elevation.
Let E be the angle of elevation from the car to the end of the ramp. We now know that the hypotenuse of our triangle measures 445 feet, and the opposite side measures 80 feet, so we need a trig function that relates our angle of elevation with the hypotenuse and the opposite side. That function is sine:
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We can conclude that the angle of elevation from the car to the end of the ramp is 10.36°.

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Answer:

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Step-by-step explanation:

Go through the picture step by step.

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Plz help me with my math
dsp73

If the area is 10 square meters than double that is area of a rectangle with height = 5m and base of 4m because height • base should produce 20m^2.

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Problem 8
spayn [35]

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