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amid [387]
3 years ago
12

If the price of a sweater was $37.38 after a 35% discount, what was the original price? Round your answer to the nearest cent.

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer:

$57.51

Step-by-step explanation:

If the price of a sweater was $37.38 after a 35% discount, what was the original price? Round your answer to the nearest cent.

The formula for the original price =

= Sales price/1 - Percentage discount

Percentage discount = 35% = 0.35

Original price = $37.38/1 - 0.35

= $37.38/0.65

= $57.507692308

Approximately = $57.51

Therefore, the original price H= $57.51

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john is cutting wood planks. He has a 3 foot plank. he needs to cut them in 3/8 length pieces. How many pieces will he have?
mojhsa [17]

Answer:

he will have 3 pieces

Step-by-step explanation:

3/8×8

=3

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4 0
2 years ago
Select whether the equation has a solution or not.<br> √x = 7
Ierofanga [76]

Answer:

x = 49

The equation does have a solution

Step-by-step explanation:

The sqrt of x = 7, does have a solution. Simply remove the radical, and raise each side by the index of the radical.

In more basic terms, what number has the sqrt of 7? 7^2 is equal to 49!

6 0
3 years ago
a culture started withwith 2,000 bacteria. after 6 hours, it grew to 2,200 bacteria. predict how many bacteria will be present a
Vilka [71]
I think the answer is 2,400
6 0
2 years ago
How do you find DE, Round to nearest 10th
Sergeu [11.5K]

Answer:  DE\approx6.0

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

cos\alpha=\frac{adjacent}{hypotenuse}

From the figure you can identify that:

\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE

Then, you can substitute values:

cos(53\°)=\frac{DE}{10}

The next step is to solve for DE in order to find its value. This is:

10*cos(53\°)=DE\\\\DE=6.01

Finally, rounding the result to the nearest tenth, you get that this is:

DE\approx6.0

7 0
3 years ago
Find the nature of the root
GREYUIT [131]

Answer:

1) Real and same.

2) Real and distinct

3) Real and distinct

4) Real and distinct

5) Real and distinct

6) Real and distinct

7) Real and distinct

8) Real and distinct

Step-by-step explanation:

If a quadratic equation is in the form of ax² + bx + c = 0, then Discriminant of the equation D = b² - 4ac, which governs the nature of roots the equation has.

If D > 0, then there will be two different real roots.

If D = 0, then two same and real roots.

If D < 0, then two distinct but imaginary roots.

Now, 1) x² + 6x + 9 = 0 has D = 6² - 4 × 9 × 1 = 0. So, there will be two same and real roots.

2) 5x² - x = 4x² + 2

⇒ x² - x - 2 = 0

It has D = (-1)² - 4 × 1 × (-2) = 9. Therefore, the roots will be two distinct and real.

3) \frac{2}{x} + \frac{3}{x} = x - 4

⇒ 5 = x² - 4x

⇒ x² - 4x - 5 = 0.

So, D = (-4)² - 4 × (1) × (- 5) = 36. So, the equation has two real and distinct rools.

4) x(x - 5) = 4(5 - x)

⇒ x² - x - 20 = 0

Hence, D = (-1)² - 4 × 1 × (-20) = 81

So, the roots will be real and distinct.

5) x² + 7x + 1 = 0 has D = 7² - 4 × 1 × 1 = 45

So, the roots will be real and distinct.

6) 2x² + 9x + 3 = 0, has D = 9² - 4 × 2 × 3 = 57.

Hence, the roots will be real and distinct.

7) 5x² - 6 = 13x

⇒ 5x² - 13x - 6 = 0

So, D = (-13)² - 4 × 5 × (-6) = 289

So, the roots will be real and distinct.

8) x² - x = 3(x + 7)

⇒ x² - 4x - 21 = 0

It has D = (-4)² - 4 × 1 × (-21) = 100

So, the roots will be real and distinct. (Answer)

6 0
3 years ago
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