What is cos 30? A b or c

Need help please ..

Strike441 [17]

Answer:

x = -11

Step-by-step explanation:

I'm assuming it's an isosceles triangle so 32 + 2x = 10;

subtract 32 from both sides;

2x = -22

x = -11

3 0

3 years ago

Help me solve (b) in this quadrilateral

Savatey [412]

Answer:

b = 87°

Step-by-step explanation:

In order to answer this question, we need to utilise an important angle fact which is <em>angles in a quadrilateral add up to 360° </em>

Using the information we can set up an equation to find the value of b

→ Form equation

63 + 140 + 70 + b = 360

→ Simplify

273 + b = 360

→ Minus 273 from both sides isolate b

b = 87°

3 0

3 years ago

Read 2 more answers

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago

Pls help me and i will know if it is wrong

DENIUS [597]

9514 1404 393

Answer:

90 miles

Step-by-step explanation:

Let d represent the distance to Grandma's house.

The speed going was ...

speed = distance/time

speed = d/2

The speed coming home was ...

speed = d/2.25

The difference of these speeds is 5 miles per hour:

d/2 -d/2.25 = 5

2.25d -2d = 5(4.50) . . . . . multiply by 4.50

0.25d = 22.5 . . . . . . . . . . .simplify

d = 90 . . . . . . . . . . . . . . . . multiply by 4

Grandma's house is 90 miles away.

8 0

3 years ago

If x=-7 and y=4 what would x^2-3xy=

Kruka [31]

Answer:

While x = -7 and y = 4, x² - 3xy = 133.

Step-by-step explanation:

x² - 3xy

Substitute variables.

(-7)² - 3(-7)(4)

Square -7 remembering that (-x)² = x².

49 - 3(-7)(4)

Multiply -7 and 4.

49 - 3(-28)

Multiply -3 and -28.

49 + 84

Add 49 and 84.

133

3 0

2 years ago