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inna [77]
3 years ago
9

Find all the values of x (where 0 < or equal to x and x < pi/2) in terms of pi for which cos(6x)=0

Mathematics
1 answer:
statuscvo [17]3 years ago
5 0
         cos(6x) = 0
cos⁻¹[cos(6x)] = cos⁻¹(0)
                 6x = 90
                  6      6
                    x = 15°
                    x = ¹/₁₂π radians

         cos(6x) = 0
<span>cos⁻¹[cos(6x)] = cos⁻¹(0)
</span>                 6x = 270
                  6       6
                    x = 45
                    x = ¹/₄π radians

         cos(6x) = 0
<span>cos⁻¹[cos(6x)] = cos⁻¹(0)
</span>                 6x = 450
                  6       6
                    x = 75
                    x = ⁵/₁₂π radians
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