Find all the values of x (where 0 < or equal to x and x < pi/2) in terms of pi for which cos(6x)=0
1 answer:
cos(6x) = 0 cos⁻¹[cos(6x)] = cos⁻¹(0) 6x = 90 6 6 x = 15° x = ¹/₁₂π radians cos(6x) = 0 <span>cos⁻¹[cos(6x)] = cos⁻¹(0) </span> 6x = 270 6 6 x = 45 x = ¹/₄π radians cos(6x) = 0 <span>cos⁻¹[cos(6x)] = cos⁻¹(0) </span> 6x = 450 6 6 x = 75 x = ⁵/₁₂π radians
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It is 52. Here is why... <span>5 + 6 x 3 + (7 - 3) x (16 divided by 2) - 3 </span>= 5+18+4 <span>x 8-3 =5+18+ 32-3 =23+32-3 =55-3 =52 If you have any more question,please feel free to ask me. ;)</span>