Answer:
Boiling point of jet fuel = 165 degrees Celsius
Step-by-step explanation:
Given:
Boiling point of jet fuel = 329°F
Find:
Boiling point of jet fuel in degrees Celsius
Computation:
C = [5/9][F – 32]
C = [5/9][329 – 32]
C = 165
Boiling point of jet fuel = 165 degrees Celsius
The answer is 16 square meter
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Answer:
a = 3
Step-by-step explanation:
Factorize (x+5)(x-4)(x+2)
(x+5)(x-4)(x+2)
= (x²-4x+5x-20)(x+2)
= (x²+x-20)(x+2)
= (x³+2x²+x²+2x-20x-40)
= x³+3x²-18x -40
Compare with x^3+ax^2
3x² = ax²
3 = a
Rearrange
a = 3
Hence the value of a that makes the expressions identical is 3
The real answer would be 0.601 kilograms.
1 gram plus 600 grams would equal 601 grams. That then is divided by 1000 because one kilogram equals 1000 grams.
Once you divide 601 and 1000, you then get 0.601
Answer:
it would be 3
Step-by-step explanation:
anything above 5, goes to the nearest, (in this case, whole number)
so it would be 3. hope this helped
