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3 years ago

Dan spends 2/5 of his wages on rent and 1/2 on food. If he makes £540 per week, how much money does he have left?

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

3 0

Answer:

Dan has £54 left

Step-by-step explanation:

Dan's weekly wages are £540.

Then his spending includes (2/5)w + (5/10()w, or (9/10)w, and this is subtracted from Dan's wages: £540 - (expenses)

£540 - (9/10)(£540) = £54

Dan has £54 left after having spent 9/10 of his weekly wages on rent and food.

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Jace's average gross pay is $1,630.00 bi-weekly. Determine how many years it will take Jace to earn his first million dollars.

vesna_86 [32]

The number of years it will take to earn his first million is 24 years

Average bi-weekly gross pay = $1,630

Bi-weekly = 2 weeks

Number of 2 weeks(bi-weeks) in a year = 26 bi-weeks

The least million he can earn is $1,000,000

Let the number of years = n

We could use the equation :

Least million = gross pay × (Number of bi-weeks × number of years)

1000000 = 1630 × (26n)

1000000 = 42380

Divide both sides by 34230

1000000 / 42380 = n

n = 23.59

The least number of years is 24.

Learn more : brainly.com/question/18796573

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Answer:

Step-by-step explanation:

8 squares=32

8 half squares=16

32+16=48

There are 4 sides to a 8 whole squares 8*4=32

There a 2 sides to 8 half squares 8*2=16

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3 years ago

What must be the value of x so that lines a and b are<br> parallel lines cut by transversal f?

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3 years ago

Parallel to y=2÷3x+6<br> Passes through (6,7)

erma4kov [3.2K]

Answer:

Step-by-step explanation:

Parallel to y=2÷3x+6

Passes through (6,7)

slope is (2/3)

Solve for when y is 7 and x is 6.

take out the + 6 at the end because it doesnt change the slope. replace with b. (y=mx+b)

replace y and x.

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3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

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3 years ago