I think the correct answer from the choices listed above is option A. The statement that determines how many batches of cookies he can make would be that he <span> can make fewer than 13 batches of cookies. Hope this answers the question. Have a nice day.</span>
Answer:
Step-by-step explanation:
If you graph there would be two different regions. The first one would be
And the second one would be
.
If you rotate the first region around the "y" axis you get that
And if you rotate the second region around the "y" axis you get that
And the sum would be 2.51+4.188 = 6.698
If you revolve just the outer curve you get
If you rotate the first region around the x axis you get that
And if you rotate the second region around the x axis you get that
And the sum would be 1.5708+1.0472 = 2.618
Answer:
Root 181
Step-by-step explanation:
Using distance formula, we know that the answer will be the square root of 181. Unfortunately, this is not a perfect square, and it is prime, so that number will remain the same.
Distance Formula: 
Hope this helped!
Answer:
x is form
Step-by-step explanation:
Answer:
Step-by-step explanation:
A system of linear equations is one which may be written in the form
a11x1 + a12x2 + · · · + a1nxn = b1 (1)
a21x1 + a22x2 + · · · + a2nxn = b2 (2)
.
am1x1 + am2x2 + · · · + amnxn = bm (m)
Here, all of the coefficients aij and all of the right hand sides bi are assumed to be known constants. All of the
xi
’s are assumed to be unknowns, that we are to solve for. Note that every left hand side is a sum of terms of
the form constant × x
Solving Linear Systems of Equations
We now introduce, by way of several examples, the systematic procedure for solving systems of linear
equations.
Here is a system of three equations in three unknowns.
x1+ x2 + x3 = 4 (1)
x1+ 2x2 + 3x3 = 9 (2)
2x1+ 3x2 + x3 = 7 (3)
We can reduce the system down to two equations in two unknowns by using the first equation to solve for x1
in terms of x2 and x3
x1 = 4 − x2 − x3 (1’)
1
and substituting this solution into the remaining two equations
(2) (4 − x2 − x3) + 2x2+3x3 = 9 =⇒ x2+2x3 = 5
(3) 2(4 − x2 − x3) + 3x2+ x3 = 7 =⇒ x2− x3 = −1
