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2 years ago

Can someone rewrite 6x + 2y = -144 as a slope intercept equation?

Mathematics

1 answer:

SVEN [57.7K]2 years ago

4 0

Answer:

y = -3x -72

Step-by-step explanation:

$6x+2y=-144\\\\2y=-6x-144\\\\y=\frac{-6}{2}x-\frac{144}{2}\\\\y=-3x-72$

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Considere as seguintes afirmações: I. O inverso de 0,2 é 5. II. O triplo de \frac{2}{5} é \frac{6}{15}. III. A metade de 0,5 é \

Alex777 [14]

Answer:

I e III

Step-by-step explanation:

Recebemos declarações na questão acima para considerar.

Declaração I. O inverso de 0,2 é 5.

Matematicamente, isso é escrito como:

1 / 0,2

0,2 = 2/10

Portanto: 1 ÷ 2/10 = 1 × 10/2

= 5

Afirmação 1 é verdadeira

Declaração II.

O triplo de 2/5 é 6/15.

Triplo de 2/5 = 2/5 + 2/5 + 2/5

= 2 + 2 + 2/5

= 6/5

= 1 1/5

Declaração II é falsa

III. A metade de 0,5 é 1/5

1/2 de 0,5

= 1/2 × 0,5 = 0,25

Convertendo em fração

= 0,25 = 25/100

= 1/4

Declaração III está correta

Portanto, as afirmações verdadeiras são I e III

8 0

2 years ago

What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)

dybincka [34]

Answer:

amplitude; $\frac{2}{3}$

Phase shift; $\pi$ units right

Period; $\frac{2\pi}{3}$

Step-by-step explanation:

The given function is

$y=-\frac{2}{3}\cos(3t-3\pi)$

This function is of the form;

$y=A\sin (Bt+C)$

The period is given by:

$|A|=|-\frac{2}{3}|= \frac{2}{3}$

The period is given by:

$T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}$

The phase shift is given by;

$\frac{C}{B}=\frac{-\3pi}{3}=- \pi$ or $\pi$ units right.

4 0

3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago

I need some help with a math problem

alina1380 [7]

Answer:

3m-25>68

Step-by-step explanation:

Your Welcome

Btw- I didn't write a step by step explanation cause it doesn't need one.

4 0

2 years ago

there were three full pizzas sitting on the counter. if joe ate 1/4 of a pizza,rhoda at 3/8 of a pizza,and chris ate 4 slices, h

IrinaK [193]

ANSWER:
15 SLICES

Explanation:
Joe ate 2 slices (1/4 = 2/8), Rhoda ate 3 (3/8), Chris ate 4.
2+3+4= 9.
There are 3 pizzas divided into 8 slices per pizza.
3 x 8 = 24 ; 24 SLICES TOTAL
Subtract 9 (that’s what was consumed) from 24.
24-9 = 15 ; 15 SLICES LEFT OVER

pls mark brainliest hehe

6 0

2 years ago