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3 years ago

Pls answer this quick as possible

Physics

1 answer:

mihalych1998 [28]3 years ago

7 0

Answer:

The answer is the 4th one

Explanation:

Good luck man

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The uncertainty in position of a proton confined to the nucleus of an atom is roughly the diameter of the nucleus. If this diame

irakobra [83]

Answer: The uncertainty in proton's momentum is $1.3\times 10^{-20}kg.m/s$

Explanation:

The equation representing Heisenberg's uncertainty principle follows:

$\Delta x.\Delta p\geq \frac{h}{2\pi}$

where,

$\Delta x$ = uncertainty in position = d = $7.8\times 10^{-15}m$

$\Delta p$ = uncertainty in momentum = ?

h = Planck's constant = $6.627\times 10^{-34}kgm^2/s^2$

Putting values in above equation, we get:

$\Delta p=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 7.8\times 10^{-15}m}\\\\\Delta p=1.3\times 10^{-20}kg.m/s$

Hence, the uncertainty in proton's momentum is $1.3\times 10^{-20}kg.m/s$

5 0

3 years ago

"Find the total weight of an 18-ft3 tank of oxygen if the oxygen is pressurized to 184 psia, the tank itself weighs 150 lbf, and

Fiesta28 [93]

Answer:

Explanation:

1 psi = 6894.76 Pa

P = 184 psi = 12.686 x 10⁵ Pa .

Temperature T = 95⁰F = 35⁰C= 308 K

volume V = 18 ft³ = 18 x 0.0283168 m³

= .51 m³

From the gas law

PV/RT = n where n is mole of gas

= 12.686 x 10⁵ x .51 / 8.31 x 308

= 252.78 gm mole

= 252.78 x 32 gm

= 8.08896 kg

= 2.20462 x 8.08896 lb

= 17.833 lb

= 17.833 / 32 lbf

= .5573 lbf

weight of tank = 150 lbf

Total weight = 150 + .5573

= 150.5573 lbf .

7 0

3 years ago

What is a physiotherapist

iragen [17]

Physiotherapists help people affected by injury, illness or disability through movement and exercise, manual therapy, education and advice

6 0

3 years ago

Read 2 more answers

A small rocket is launched vertically, attaining a maximum speed at burnout of 1.0 102 m/s and thereafter coasting straight up t

vova2212 [387]

Vf^2 = vo^2 + 2ad

vf = 0 m/s
a = -9.8

0 = 10404 + 2 (9.8)d

10404 = 2 (9.8) d

d = 530.816

1528 - 530.816 = 997.184

Hope this helps

3 0

3 years ago

If I am plotting a graph to my physics practical result. If they ask me to find the x-intercept, what should I consider when plo

Virty [35]

Answer:

• When getting x-intercept, your vertical axis or y-axis must have it's callibration and demarcation starting from zero.

Explanation:

As well as when getting y-intercept, your horizontal axis or x-axis must have it's callibration and demarcation starting from zero.

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7 0

3 years ago