1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeyben [28]
2 years ago
11

What's wrong with the following statement? “The racing car turns around

Physics
1 answer:
Artemon [7]2 years ago
8 0
You cant turn corners at at constant velocity, you would hav to slow down.
You might be interested in
Plzzzzzzzzzzzzzzzzz help
makkiz [27]

Answer:

a or b

Explanation:

3 0
2 years ago
At what displacement of a sho is the energy half kinetic and half potential? what fraction of the total energy of a sho is kinet
expeople1 [14]

As we know that KE and PE is same at a given position

so we will have as a function of position given as

KE = \frac{1}{2}m\omega^2(A^2 - x^2)

also the PE is given as function of position as

PE = \frac{1}{2}m\omega^2x^2

now it is given that

KE = PE

now we will have

\frac{1}{2}m\omega^2(A^2 - x^2) = \frac{1}{2}m\omega^2x^2

A^2 - x^2 = x^2

2x^2 = A^2

x = \frac{A}{\sqrt2}

so the position is 0.707 times of amplitude when KE and PE will be same

Part b)

KE of SHO at x = A/3

we can use the formula

KE = \frac{1}{2}m\omega^2(A^2 - x^2)

now to find the fraction of kinetic energy

f = \frac{KE}{TE} = \frac{A^2 - x^2}{A^2}

f = \frac{A^2 - (\frac{A}{3})^2}{A^2}

f_k = \frac{8}{9}

now since total energy is sum of KE and PE

so fraction of PE at the same position will be

f_{PE} = 1 - f_k

f_{PE} = 1 - (8/9) = 1/9

7 0
3 years ago
Sheila eats an energy bar right before she goes on a run. What energy changes will occur in sheila as she runs after eating?
LiRa [457]
The energy bar eaten by Sheila has chemical energy locked up inside it. This chemical energy is converted to mechanical energy in form of potential and kinetic energy and this in turn is converted to heat energy as the run progresses. Thus, the energy changes are: chemical energy to mechanical energy [kinetic and potential] and finally to heat energy.
8 0
2 years ago
Read 2 more answers
Total potential and kinetic energy of an object.
Ne4ueva [31]

Answer:

The Total Mechanical Energy

As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Explanation:

8 0
3 years ago
You are traveling at 14 m/s for 20 seconds. What is your displacement?
enyata [817]

Velocity = 14 m/s

Time = 20 s

Displacement = Velocity×Time = (14×20) m = 280 m

The displacement is 280 m towards the direction of motion.

5 0
2 years ago
Read 2 more answers
Other questions:
  • A fish appears to be 2.00 m below the surface of a pond (nwater = 1.33) when viewed almost directly above by a fisherman. What i
    7·2 answers
  • A snail travels at a rate of 2.37 feet per minute. a. Write a rule to describe the function. b. How far will the snail travel in
    5·2 answers
  • a ferryboat has an acceleration of 0.50 m/s. If the ferry travels 125m in 20 seconds while accelerating, what was its initial ve
    8·1 answer
  • Matter and energy cycle around our ecosystem, are never being created or destroyed.
    6·2 answers
  • A fixed mass of an ideal gas has a volume of 800 cm3 under certain conditions. The pressure (in kPa) and temperature (in K) are
    14·1 answer
  • Use the drop-down menus to complete the statement.
    14·2 answers
  • Two horizontal pipes have the same diameter, but pipe B is twice as long as pipe A. Water undergoes viscous flow in both pipes,
    6·1 answer
  • What is variable velocity?​
    14·2 answers
  • The variable ______________ describes how quickly something moves.
    7·1 answer
  • I wanna cry<br> I literally made this account like a year ago and my username still applies
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!