Answer:
106 ft
Step-by-step explanation:
Assuming the shadow is measured along horizontal ground.
tanθ =opp/adj = building height/shadow length
building height = shadow length(tanθ)
h = 61tan60
h = 105.65509...
Answer:
24
Step-by-step explanation:
Answer:x=750
Step-by-step explanation:
2/3(x)+ 1/4(x) + 375
(9/12)x - (3/12)x = 375
(6/12)x + 375
Answer:

Step-by-step explanation:
Given:
Given point P(6, 6)
The equation of the line.

We need to find the equation of the line perpendicular to the given line that contains P
Solution:
The equation of the line.

Now, we compare the given equation by standard form 
So, slope of the line
, and
y-intercept 
We know that the slope of the perpendicular line 



So, the slope of the perpendicular line
From the above statement, line passes through the point P(6, 6).
Using slope intercept formula to know y-intercept.

Substitute point
and 




So, the y-intercept of the perpendicular line 
Using point slope formula.

Substitute
and
in above equation.

Therefore: the equation of the perpendicular line 