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Citrus2011 [14]
3 years ago
9

CH3-C(CH3)=CH-CH=CH2 + HBr-> ?

Chemistry
1 answer:
Sergio [31]3 years ago
6 0
CH3(CH3)=CH-CH(BR)-CH3
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Is this right? I did the math and everything but it just wondering if it's right
hichkok12 [17]
Seems correct. Your steps make sense, the molar ratios are right and you've done it in a clear easy to follow manner. I see no issues with it. 
4 0
3 years ago
Read 2 more answers
1. Calculate the average reaction rate expressed in moles H2 consumed per liter per second.
valentina_108 [34]

Answer:

1) 0.0025 mol/L.s.

2) 0.0025 mol/L.s.

Explanation:

  • For the reaction:

<em>H₂ + Cl₂ → 2HCl.</em>

<em></em>

<em>The average reaction rate = - Δ[H₂]/Δt = - Δ[Cl₂]/Δt = 1/2 Δ[HCl]/Δt</em>

<em></em>

<em>1. Calculate the average reaction rate expressed in moles H₂ consumed per liter per second.</em>

<em></em>

The average reaction rate expressed in moles H₂ consumed per liter per second = - Δ[H₂]/Δt = - (0.02 M - 0.03 M)/(4.0 s) = 0.0025 mol/L.s.

<em>2. Calculate the average reaction rate expressed in moles CI₂ consumed per liter per second.</em>

<em></em>

The average reaction rate expressed in moles Cl₂ consumed per liter per second = - Δ[Cl₂]/Δt = - (0.04 M - 0.05 M)/(4.0 s) = 0.0025 mol/L.s.

7 0
3 years ago
Ao<br>25% of 80 =<br>please help me asap ​<br>this is math btw not chem
mestny [16]

Answer:

55

Explanation:

if you sub and I am writing it simple

3 0
3 years ago
Read 2 more answers
6th grade science if you can help me thanks :)
Blizzard [7]

Answer:

weather tis is answer for que

5 0
3 years ago
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How can the properties of ionic compounds be used to determine the identity of an unknown mixture of ions?
Yanka [14]

Answer: By carrying out series of wet test

Explanation: Dissolve the ionic compound in water. Ionic compounds will ionise and allow the solution to conduct an electric current. Afterwards specific test will be carried out to detect the presence of cations and anions. Another way would be to find the substance's melting point. Ionically bonded compounds have much higher melting points.

7 0
3 years ago
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