Question

Show the calculation of the mole fraction of each gas in a 1.00 liter container holding a mixture of 8.65 g of CO2 and 4.32 g of SO2 at 25oC.

Answer 1

Answer:

0.745 and 0.245

Explanation:

Mole fraction (χ) is  the number of moles of a component divided by the total number of moles in a mixture.  

We must calculate the moles of each component.  

Let CO₂ be Gas 1 and SO₂ be Gas 2.

1. Calculate the moles of each gas.

$\text{n} _{1} = \text{8.65 g} \times \dfrac{\text{1 mol}}{\text{44.01 g}} = \text{0.1965 mol}\\\\\text{n} _{2} = \text{4.32 g} \times \dfrac{\text{1 mol}}{\text{64.06 g}} = \text{0.067 44 mol}$

2. Calculate the total moles.

$n_{\text{tot}} = \text{n}_{1} + \text{n}_{2} = \text{0.1965 mol} +\text{0.067 44 mol} = \text{0.2640 mol}$

3. Calculate the mole fraction of each component

$\chi_{1} =\dfrac{0.1965}{0.2640} = \mathbf{0.745}\\\\\chi_{2} =\dfrac{0.06744}{0.2640} = \mathbf{0.255}$