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Doss [256]
3 years ago
9

Simone is making a scale drawing of a famous building. In reality, the building is 108 meters tall. In her drawing, the building

is 4 ½ inches tall. How wide should the scale drawing be if the actual width is 48 meters?
Mathematics
1 answer:
Reika [66]3 years ago
7 0
4 1/2 over 108
? Over 48
Answer 2
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Rhonda bought a new laptop for $800. The laptop depreciates, or loses, 20% of its value each year. The value of the laptop at a
zhuklara [117]

As per the problem,

Rhonda bought a new laptop for $800.

The laptop depreciates, or loses, 20% of its value each year.

The value of the laptop at a later time can be found using the formula

A=P(1-r)^t.....(1)

Here we have

P=$800

r=20%=0.20

t=2 years

Substitute the values in equation (1) we get

A=800(1-0.2)^2\\ \\ \Rightarrow A=800(0.8)^2\\ \\ \Rightarrow A=800*0.64\\ \\ \Rightarrow A=512\\

The laptop be worth in two years will be $512.

6 0
3 years ago
CAN SOMEONE CHECK MY WORK GEOMETRY PEOPLE ONLY PLS
quester [9]

Answer:

Is the graph shown the initial triangle, or the translated one?

Step-by-step explanation:

4 0
3 years ago
Let f(x)=x^2-5x+8 and g(x)=x^2-4 (f-g)(x)=
Bogdan [553]
What you do here is subtract g from f: x^2 - 5x + 8 - (x^2 -4); x^2 - 5x + 8 - x^2 + 4; Rearranging gives you x^2 - x^2 - 5x + 8 + 4 which is, simplified, -5x + 12
8 0
3 years ago
Find BC please in the picture
tatiyna

B. 25 Km. The measure of BC is 25 km.

The easiest way to solve this problem is using the cosine theorem c = √a²+b²-2ab*cos A.

BC = √AC²+AB²-2(AC)(AB)*cos A

BC = √(21km)²+(14km)²-2(21km)(14km)*cos 89°

BC = √441km²+196km²-588km²*(0.017)

BC =√637km²-10.26km²

BC = √636.74km²

BC = 25.03km ≅ 25

7 0
3 years ago
An object is moved at a constant speed of 20m/s for 4s
konstantin123 [22]

Answer:

80 m is distance traveled

Step-by-step explanation:

if object moves at 20m/s, then in 4 seconds the expression 20 x 4 is used to get 80. 80 m traveled

3 0
2 years ago
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