Answer:
First split the fraction.
2t/sqrt(t) + 3/sqrt(2)
2(t^0.5) + 3(t^-0.5)
Add 1 to the power, divide by the new power
2(t^1.5)/1.5 + 3(t^0.5)/0.5
4t^(3/2)/3 + 6t^(1/2) + c
4t×sqrt(t)/3 + 6sqrt(t) + c
El conjugado de a+bi es a-bi (<span>invierta el signo de la parte imaginaria)
</span>
<span>por lo tanto
</span><span>El conjugado de 3+4i es 3-4i,
</span><span>El conjugado de 6-i es 6+i</span>
Answer:
Q1 --> 17
Q2 --> 20
Q3 --> 22.5
Interquartile
Range IQR 5.5
Step-by-step explanation:
Step 1
We rearrange the given data set
10, 16, 18, 20, 20, 21, 24, 25
Q2 (median):
Q1:
Q3:
Interquartile Range (IQR): Q3-Q1 -
Answer:tanA=11/60 cosA=60/61 secA=61/60
Step-by-step explanation:
From Pythagoras rule (adjacent)=√(61^2-11^2)
Adjacent=√(3721-121)
Adjacent=√(3600) adjacent=60
Opposite=11 hypotenuse=61 adjacent=60
TanA=11/60 cosA=60/61 secA=61/60
