I need help again omf im so sorry

Imagine that you are doing an exhaustive study on the children in all of the daycares in your school district. You are particula

alisha [4.7K]

Answer: The difference between M and mu is due to the sampling error is -6.59 .

Step-by-step explanation:

As per given:

in population, the average number of minutes spent in active play on weekends is μ = 65.87

In sample, the average number of minutes the children spend in active play on weekends is M = 59.28

Now, the difference between M and μ is due to the sampling error is M- μ

= 59.28 - 65.87

= -6.59

So, the difference between M and mu is due to the sampling error is -6.59 .

8 0

4 years ago

The moon appears red during a lunar eclipse because red is the __________ wavelength of light in the color spectrum present in s

Sav [38]

Answer:

Longest

Step-by-step explanation:

The moon appears red during a lunar eclipse because red is the Longest wavelength of light in the color spectrum present in sunlight.

-Please Mark As Brainliest

8 0

3 years ago

If a soccer team made 24 penalty shot out of 100 what fraction and what percentage of penalty shots did the team miss?

saul85 [17]

76/100 or 76% of the shots

8 0

4 years ago

Every day, Luann walks to the bus stop and the amount of time she will have to wait for the bus is between 0 and 12 minutes, wit

Nana76 [90]

Answer:

a. 341.902.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n instances of a normal variable:

For n instances of a normal variable, the mean is $n\mu$ and the standard deviation is $s = \sigma\sqrt{n}$

60 days, for each day, mean 6, variance of 12.

So

$\mu = 60*6 = 360$

$s = \sqrt{12}\sqrt{60} = 26.8328$

What is the 25th percentile of her total wait time over the course of 60 days?

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{s}$

$-0.675 = \frac{X - 360}{26.8328}$

$X - 360 = -0.675*26.8328$

$X = 341.902$

Thus, the correct answer is given by option A.

3 0

3 years ago

Find the solution of the given initial value problem: y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$