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mariarad [96]
3 years ago
14

I need help again omf im so sorry

Mathematics
1 answer:
Elodia [21]3 years ago
5 0

Answer:

I'm pretty sure Dave is correct

Step-by-step explanation:

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Refer below explanation.

Step-by-step explanation:

Given :  two triangles ∆QPK and ∆LMK.

We have to show  ∆QPK ≅ ∆LMK.

Two triangles are similar if ratio of the corresponding sides are equal and measure of corresponding angles are equal.

Statement 1)

QK=16, PK=26, MK=65, KL=40 ( Reason: Given)

Statement 2 )

\frac{QL}{KL}=\frac{16}{40} \\\\\frac{PK}{KM} =\frac{26}{65}

(reason : ratio of corresponding sides)

Statement 3)

\frac{QL}{KL}=\frac{16}{40}=\frac{2}{5} \\\\\frac{PK}{KM} =\frac{26}{65}=\frac{2}{5}

Thus, \frac{QL}{KL}=\frac{PK}{KM} =\frac{2}{5}

(reason: simplify ratios)

Statement 4)

∠MKL = ∠PQK (reason : Vertically opposite angles)

Statement 5)

∆QPK ≅ ∆LMK (reason : Side-angle-side)

Side angle side similarity criterion states that two angles are similar if the ratio of their corresponding sides and angle between these sides are equal then triangles are similar.




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