I need help ASAP!!!!!!!!!!!!!!!!!!!!

PLEASEEE HELP ME!!!!!!!! (assume no variable equals 0) will give brainly

Aleks04 [339]

SOLVING WITH THESE VALUES:

x=2

y=3

——————————————————

$\frac{8(2)^9(3)^3-12(2)^8(3)^2+2(2)^3(3)}{2x^3y}$

The answer is 1,729 when x=2 and y=3

Work is in the pictures below :)

Picture 1: Solved where x=2 and y=3

Picture 2: Solved without plugging in values for x and y

6 0

3 years ago

Read 2 more answers

The question is about trigonometry solving two sides it is a right triangle hypotenuse is X left side is 20 bottom side is 21 i

elena55 [62]

Answer:

x = 29

Angle A = 46.4°

Angle B = 43.6°

Step-by-step explanation:

Since it is a right angle triangle, we can find x from pythagoras theorem;

x = √(20² + 21²)

x = √(400 + 441)

x = √841

x = 29

Using trigonometric ratios we can find angles A and B.

Opposite is 20

Adjacent is 21

Thus; opp/adj = tan B

20/21 = tan B

B = tan^(-1) 0.9524

B = 43.6°

Sum of angles in a triangle is 180°. Thus;

A = 180 - (90 + 43.6)

A = 46.4°

4 0

2 years ago

The base of a building is shaped like a parallelogram. The first floor has an area of 1575 square feet. If the base of this para

lorasvet [3.4K]

Answer:

No, the height cannot be 25 feet because the resulting area is inconsistent with the information given.

Step-by-step explanation:

Given that the base of the first floor is 75 feet, we can answer this question in two different ways:

1) Solve for Area using the given height and compare the results to that of the question.

Using the formula for Area:

A = b x h,

A = (75) x (25) = 1875

Because the given height results in an area of 1875 feet, and not 1575 feet, the base of this parallelogram cannot be 25 feet.

2) Solve for Height using the given base and Area

Using the formula for Height:

h = A / b,

h = (1575) / (75) = 21 ft

The base of this parallelogram could not be 25 feet because when solving for height using the given base and area, the resulting measurement is 21 feet.

8 0

3 years ago

Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls

murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}$

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= $(\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111$

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

$= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222$

Hence,

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684$