The volume and surface area of the pyramid will be 392 / 3 cubic units and 189 square units. Then the correct option is A.
The complete question is attached below.
<h3>What is the volume and surface area of the pyramid? </h3>
Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.
Then the volume of the pyramid will be
V = (L × B × H) / 3
The surface area of the pyramid will be
SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)
Then the volume will be
V = (7 × 7 × 8) / 3
V = 392/3 cubic units
Then the surface area will be
SA = 2(1/2 × 7 × 10) + 2(1/2 × 7 × 10) + (7 × 7)
SA = 189 square units
Then the correct option is A.
More about the volume and surface area of the pyramid link is given below.
brainly.com/question/23302816
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Answer: a) c(x) = 0.124x + 1.1, b) 13 units
Step-by-step explanation: Revenue function = R(x) = 0.21x
Profit function = p(x) = 0.086 - 1.1
Cost function = c(x) =?
A)
Recall that profit = total revenue - total cost
Hence, total cost = total revenue - profit
c(x) = 0.21x - (0.086x - 1.1)
c(x) = 0.21x - 0.086x + 1.1
c(x) = 0.124x + 1.1
B)
Break even point is the point where total revenue equals total cost
R(x) = c(x)
0.21x = 0.124x + 1.1
0.21x - 0.124x = 1.1
0.086x = 1.1
x = 1.1/0.086
x = 12.79 which is approximately 13 units
The formula for the volume of a cone is V=(1/3)πr^2h.
To find r (radius) divide the diameter by 2, giving you 2.5 cm.
Plug in the numbers now !
V=(1/3)(3.14)(2.5^2)(9)
V=(1/3)(3.14)(6.25)(9)
V=(1/3)(176.625)
V=58.875
Therefore, the volume of the cone is about 59cm^3 :)
Y= 1/10x + 2/10 is what you are left with once the equation is simplified
