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levacccp [35]
3 years ago
5

Find one length of the square (7x-3) 3(x+1)

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0

Area of a square = Side × Side

Side = 7x-3

Area of the square = (7x-3) × (7x-3)

= 7x(7x-3) -3(7x-3)

= 49x^2 -21x -21x +9

=49x^2 -42x +9

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Answer:

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90 / 9 does equal 10, but 90 / -9 equals -10.

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Hello :
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