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1 year ago

Jim went on a fishing holiday.The histogram shows some ingormation about the weights of the fish he caught.

Mathematics

1 answer:

pav-90 [236]1 year ago

7 0

You did not put the histogram here, so I am not able to help :c

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Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.

Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.

Step-by-step explanation:

The weight of Priya's cat = $5\frac{1}{2}\ pounds$

Now, $5\frac{1}{2}=\frac{11}{2}\ pounds$

The weight of her dog = $8\frac{1}{4}\ pounds$

$8\frac{1}{4}=\frac{33}{4}\ pounds$

Let cat is n times heavy as dog.

Then $n=\text{cat's weight}\div\text{dog's weight}$

$n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}$

Hence, The cat is 2/3 times as heavy as the dog.

5 0

2 years ago

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Why do we use variables in math?

Phoenix [80]

Answer:

We use it to substitute an unknown number. We have a variable for a number we don’t know and as we solve the problem we can find the answer for the variable or unknown number.

Step-by-step explanation:

I hope it helps! Have a great day!
Anygays-

8 0

1 year ago

Read 2 more answers

Find the length of side x to the nearest tenth

navik [9.2K]

Answer:

x = 2 sqrt(3)/3

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 60 = 1 /x

x sin 60 =1

x = 1 /sin 60

x = 1 / sqrt(3)/2

x = 2 sqrt(3)/3

3 0

2 years ago

Solve number problem 8

butalik [34]

Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.

Their sum is -36, so add x and x + 2, and set equal to -36. Then solve for x to find the smaller one. Finally, 2 more than x is the greater of the two integers.

x + x + 2 = -36

2x + 2 = -36

2x = -38

x = -19

The smaller one of the two integers is -19.

x + 2 = -19 + 2 = -17

The greater of the two integers is -17.

Answer: The integers are -19 and -17.

4 0

2 years ago

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Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
to get,

$\cos(x) = \sqrt{1 - ( { \frac{3}{5} })^{2}} = \frac{4}{5}$

We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

4 0

2 years ago