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Reika [66]
3 years ago
5

Greg runs 3 miles in 28 minutes. At the same rate, how many miles would he run in 42 minutes?

Mathematics
2 answers:
Paladinen [302]3 years ago
7 0

Answer:

4.5

 miles

Step-by-step explanation:

Well, he runs

3

miles in

28

minutes. Also, see that

42

=

28

⋅

1.5

.

So, his journey would just be running

1.5

times, with each time running

28

minutes.

So, he runs a total of

1.5

⋅

3

=

4.5

miles

Dafna1 [17]3 years ago
7 0

Answer:

4.5 miles

Step-by-step explanation:

You divide 28/3 then the answer you get multiply it to 42 = 4.5.

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Miss Kito’s car holds 18 gallons of gasoline. As she was driving, she noticed that the fuel gauge indicated that she had 1/5 of
jonny [76]

We will see that the cost of filling the tank is $38.88, and at the final of the trip she will have 4 gallons on the tank.

<h3>How much costs to fill the tank?</h3>

a) The car holds 18 gallons, and it has 1/5 of the tank remaining.

Then in the tank there are:

(1/5)*18 = 3.6 gallons.

Then we need 18 gal - 3.6 gal = 14.4 gal

And each gallon costs $2.70, then to fill the tank, Miss Kito needs:

(14.4)*$2.70 = $38.88

b) Now we know that the car travels 26 miles per gallon, and she needs to travel a total distance of 364 miles.

Then she needs:

\frac{364mi}{26 mi/gal} = 14 gal

To travel that distance, and the car holds 18 gallons, so at the end of the trip, she will have 4 gallons of gasoline in her car.

If you want to learn more about algebra, you can read:

brainly.com/question/4344214

7 0
2 years ago
A ski lodge charges $26 per day for a pass and $1.50 for every ski lift ride. A second ski
malfutka [58]

Answer:

32=40

26=39

Step-by-step explanation:

8 0
2 years ago
=
enyata [817]
Umm what? I don’t think i can answer this cause i can barely read it.
8 0
3 years ago
Luis wants to buy a pair of jeans that costs $24. If the tax rate is
muminat

Answer:

25 68/100

Step-by-step explanation:

percent means 1/100th.

7 percent=7/100

24 times 7/100= 1 68/100

24+1 68/100=25 68/100

7 0
3 years ago
The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is
saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

   α = 0.05, α/2 = 0.025

  From the t tables, T.INV.2T(α, degree of freedom), we find the t value as

  t =T.INV.2T(0.05, 128) = 2.34

  Taking the positive value of t, we get  

  Confidence interval is ,

  $\overline X \pm t \times \frac{s}{\sqrt n}$

 $34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$

 (32.52, 35.8)

 95% confidence interval is  (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.  

4 0
2 years ago
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