34.607 to the nearest whole number

On the same two days, the Belly Company's Stock also began at $36. However, by the end of the first day, the stock had dropped b

sineoko [7]

It's still 36% because you droppet it and then gain it back up

8 0

4 years ago

In a sample of n = 6 scores, the smallest score is X = 3, the largest score is X = 10, and the mean is M = 6. If the largest sco

Murrr4er [49]

Answer:

8

Step-by-step explanation:

Given that in a sample of n = 6 scores, the smallest score is X = 3, the largest score is X = 10

Mean = 6

Since mean = 6 we get sum of all the 6 scores = $6(6) = 36$

Now II part says 10 is changed to 20

i.e. original sum = 36

Changed value = 10

Adjusted value =26

Add: new value =22

New sum =48

So we have sum = 48

New mean= $\frac{48}{6} =8$

(This can also be done using the formula

old mean + positive change in one score/6)

5 0

3 years ago

Hurry please <br>if 2w+13=4w-7<br>and they both equal 180<br>what is w

Gennadij [26K]

If you work out the equation the answer would be 5 but its not a definite answer.

7 0

3 years ago

Help!! what 2 numbers have a sum of -1 & multiply to make -12. I know the question is simple but I just can't work it out. P

Sholpan [36]

The answer is -4 and 3 because -4 + 3 = -1 and -4 × 3 = -12. I hope this helps!

8 0

4 years ago

Last year, a comprehensive report stated that 28% of businesses in the northeast of Ohio were considered highly profitable. This

Alik [6]

Answer:

$z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575$

$p_v =2*P(z>1.575)=0.115$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

Step-by-step explanation:

Data given and notation

n=50 represent the random sample taken

X=19 represent the businesses were highly profitable

$\hat p=\frac{19}{50}=0.38$ estimated proportion of businesses were highly profitable

$p_o=0.28$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of businesses were highly profitable is different from 0.28 or no, the system of hypothesis is.:

Null hypothesis: $p=0.28$

Alternative hypothesis: $p \neq 0.28$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>1.575)=0.115$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

4 0

4 years ago