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ivanzaharov [21]
3 years ago
8

If the endpoints of the diameter of a circle are (6, 3) and (2, 1), what is the standard form equation of the circle?

Mathematics
1 answer:
Anastasy [175]3 years ago
8 0
If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:

(x,y)=((6+2)/2, (3+1)/2)=(4,2)

Now we need to find the radius....the diameter is:

d^2=(6-2)^2+(3-1)^2

d^2=16+4

d^2=20  since d=2r, r=d/2, and r^2=d^2/4 so

r^2=5

The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
 
(h,k)=(4,2) from earlier so:

(x-4)^2+(y-2)^2=5
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Step-by-step explanation:

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Given:

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The highest degree of given equation is 2. So, the number of roots is also 2.

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Step-by-step explanation:

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Aaden wants to get a subscription to an online library. There are two subscription options, one of which charges a fixed 96 doll
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Using a system of equations, the meaning of point R is given as follows:

A number of books and their cost where both subscriptions cost the same.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable. In a graph, the solution to the system is the intersection point of the two equations.

In this problem, the point R is the point in which:

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More can be learned about a system of equations at brainly.com/question/24342899

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