Answer:
B. 60 ft²
Step-by-step explanation:
The overall area of the parallelogram is the product of its base length (15 ft) and height (8 ft), so is ...
overall area = (15 ft)(8 ft) = 120 ft²
The area of the quadrilateral in the middle of the parallelogram is the area of two triangles, each with a base equal to 15 ft (the horizontal line in the diagram), and heights that total 8 ft. If we let x represent the height of one of those triangles, then the other has a height of (8-x) and the sum of their areas is ...
quadrilateral area = (1/2)(15 ft)(x) +(1/2)(15 ft)(8 ft -x)
= (1/2)(15 ft)(x + 8 ft - x) = (1/2)(15 ft)(8 ft) = 60 ft²
Then the shaded area is the difference between the parallelogram area and the quadrilateral area:
shaded area = parallelogram area - quadrilateral area
= (120 ft²) - (60 ft²)
= 60 ft²
The area of the shaded region is 60 ft².
9514 1404 393
Answer:
a) 1/2
b) 1/2
Step-by-step explanation:
a) The average rate of change is the slope of the segment whose end points are the ends of the interval. On the interval [2, 8] the average rate of change is ...
m = (f(8) -f(2))/(8 -2) = (4 -1)/6 = 3/6 = 1/2
The average rate of change on the interval [2, 8] is 1/2.
__
b) In this context, "slope" and "average rate of change" mean the same thing. A line with the same slope will have a slope of 1/2.
E^6(3n - 4)
e^6(3(2) - 4)
e^6(6 - 4)
e^6(2)
403.4287935(2)
806.857587
Answer:
C. f(x)=-2x^3-2x^2+12x
Step-by-step explanation:
Answer:
The proof is given below.
Step-by-step explanation:
Given the two triangles which are similar we have to prove that the ratio of their angle bisectors and the side or we can say that the ratio of their altitude are proportional.
In ΔABP and ΔDEQ
∠1=∠2 (Given)
∠3=∠4 (each 90°)
By AA similarity rule ΔABP≅ΔDEQ
As if the two triangles are similar then their corresponding sides are proportional
⇒ 
Hence, Corresponding angle bisectors of similar triangles are proportional and their ratio is equal to the ratio of altitude.