A total of tickets were sold for the school play. They were either adult tickets or student tickets. There were more student tic
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Answer:
Step-by-step explanation:
Consider the following characteristics of the problem:
The numbers that are selected are different between 1 and 49. This means that the same number is not repeated twice.
The order in which the selected numbers appear does not matter:
This means that (123) = (312)
With this in mind, we know that it is a problem of combinations without repetition. It is not calculated using permutations because in the permutations the order of selection is important, for example: (123) is not equal to (312)
The formula for calculating combinations without repetition is:
Where n is the number of "elements" you can choose and choose r from them
In this case:
n=49
r=6
So:
There are 13,983,816 possible results
This is the best method to calculate the number of possible outcomes.
<em><u>"Besides your method, is there another method to determine the number of outcomes?"</u></em>
Sure, make a list of the 13,983,816 different sets of 6 numbers.
To win it is necessary to obtain the 6 winning numbers in any order. The number of ways this can occur is calculated by combining 6 in 6
Finally the probability of winning is:
Note that the probability of winning is very close to 0. It is practically impossible to win the lottery, you will probably never win anything. Therefore it is better not to invest money in this